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Murljashka [212]
2 years ago
12

1. The Yerkes-Dodson Law says

Chemistry
1 answer:
goblinko [34]2 years ago
4 0

Answer:

The Yerkes-Dodson Law suggests that there is a relationship between performance and arousal. Increased arousal can help improve performance, but only up to a certain point.

Explanation:

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If you take Organic Chemistry Laboratory (CHM2211L) you will learn the term reflux. A reaction is considered to be at reflux whe
shutvik [7]

Answer : The temperature of the chloroform will be, 101.67^oF

Explanation :

First we have to calculate the mass of chloroform.

\text{Mass of chloroform}=\text{Density of chloroform}\times \text{Volume of chloroform}=1.4832g/ml\times 74.81ml=110.958g

conversion used : (1cm^3=1ml)

Now we have to calculate the temperature of the chloroform.

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = amount of heat or energy = 1.46 kJ = 1460 J   (1 kJ = 1000 J)

c = specific heat capacity = 0.96J/g.K

m = mass of substance = 110.958 g

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25^oC=273+25=298K

Now put all the given values in the above formula, we get:

1460J=110.958g\times 0.96J/g.K\times (T_{final}-298)K

T_{final}=311.706K

Now we have to convert the temperature from Kelvin to Fahrenheit.

The conversion used for the temperature from Kelvin to Fahrenheit is:

^oC=\frac{5}{9}\times (^oF-32)

As we know that, K=^oC+273 or, K-273=^oC

K-273=\frac{5}{9}\times (^oF-32)

K=\frac{5}{9}\times (^oF-32)+273  ...........(1)

Now put the value of temperature of Kelvin in (1), we get:

311.706K=\frac{5}{9}\times (^oF-32)+273

T_{final}=101.67^oF

Therefore, the temperature of the chloroform will be, 101.67^oF

5 0
3 years ago
A 0.334 g sample of an unknown halogen occupies 109 mL at 398 K and 1.41 atm. What is the identity of the halogen?
kolezko [41]
We can use the ideal gas law equation for the above reaction to find the number of moles present 
PV = nRT 
P - pressure - 1.41 atm x 101325 Pa/atm = 142 868 Pa
V - 109 x 10⁻⁶ m³
R - 8.314 Jmol⁻¹K⁻¹
T - 398 K
substituting the values in the equation 
142 868 Pa x 109 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 398 K
n = 4.70 x 10⁻³ mol
number of moles = mass present / molar mass
molar mass = mass / number of moles  
                   = 0.334 g/ 4.70 x 10⁻³ mol = 71.06 g/mol
halogens exist as diatomic molecules 
Therefore atomic mass - 71.06 / 2 = 35.5 
halogen with 35.5 g/mol is Cl
unknown halogen is Cl
5 0
3 years ago
When an action force occurs, the reaction force is always Question 6 options: A.in the same direction as the action force. B.app
Mrac [35]
D. 100%, extremely sure. Because Newton's 3rd law states every force has an equal and opposite reaction.
7 0
2 years ago
Read 2 more answers
The fish died after living in the aquarium for many years
miv72 [106K]

In an aquarium the water quantity is limited and fish excrete ammonia through their gills and body, this dissolves in water and creates toxins.

<u>Explanation</u>:

  • In an aquarium the water quantity is limited and fish excrete ammonia through their gills and body, this dissolves in water and creates toxins. Over some time some bacteria develop in water which converts this ammonia into nitrites and then into nitrates. Till this process is complete, the aquarium remains a death trap.

There are some reasons for a fish to die early,

  • This one is common for beginners. They don’t have any idea about the nitrogen cycle. And they simply buy a fish tank and fish on the same day, go home and set it up.
  • Ammonia spikes - Even in a cycled tank, you can have occasional ammonia spikes due to overfeeding. Incompatible tank mates - If you put a too docile fish with a very aggressive cichlid, it will get harassed and eventually die due to stress.
4 0
3 years ago
What is the mass of 2.5 mol of ca, which has a molar mass of g/mol
swat32
Atomic mass Ca = 40 a.m.u

1 mole Ca ----------- 40 g
2.5 mols Ca -------- ( mass Ca )

Mass Ca = 2.5 x 40 / 1

Mass Ca = 100 / 1

= 100 g of Ca

hope this helps!
3 0
3 years ago
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