Answer:
The mass of potassium required to produce a known mass of potassium chloride
Explanation:
Stoichiometry deals with the relationship between amount of substances, mass of substances or volume of substances required in a chemical reaction. Stoichiometric relationships may involve reactants alone or reactants and products. These relationships are normally in the form of simple proportion.
A typical example is our answer option, the mass of potassium required could be used to determine the mass of potassium chloride produced after a balanced reaction equation is written.
Answer:
4 moles of SO3 will be produced from 6 moles of oxygen.
Explanation:
From the reaction given
S8 + 12 O2 ----> 8 SO3
12 moles of oxygen reacts to form 8 moles of SO3
if 6 moles of oxygen were to be used instead, it has been reduced to half of the original mole of oxygen used. Then the moles of SO3 will also be reduced to half.
6 moles of O2 will yield 4 moles of SO3
12 moles = 8 moles
6 moles = ?
? = 6 * 8 / 12
? = 48/ 12
? = 4 moles of SO3.
Answer:
a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.
Explanation:
Answer:
0.76 mole of Fe2S3.
Explanation:
Step 1:
Determination of the number of mole in 449g iron(III)bromide, FeBr3. This is illustrated below:
Mass of FeBr3 = 449g
Molar mass of FeBr3 = 56 + (80x3) = 296g/mol
Mole of FeBr3 =..?
Mole = Mass /Molar Mass
Mole of FeBr3 = 449/296
Mole of FeBr3 = 1.52 moles
Step 2:
The balanced equation for the reaction. This is given below:
2FeBr3 + 3Na2S —> 6NaBr + Fe2S3
Step 3:
Determination of the number of mole of Fe2S3 produced from the reaction of 449g ( i.e 1.52 moles) of FeBr3. This is illustrated below:
From the balanced equation above,
2 moles of FeBr3 reacted to produce 1 mole of Fe2S3.
Therefore, 1.52 moles of FeBr3 will react to produce = (1.52 x 1)/2 = 0.76 mole of Fe2S3.
Therefore, 0.76 mole of Fe2S3 is produced from the reaction.
Answer:
106.6 °C
Step-by-step explanation:
The formula for <em>boiling point elevation</em> ΔTb is
ΔTb = iKb·b
where
i = the van't Hoff i# factor
Kb = the molal boiling point elevation constant
b = the molal concentration of the solution
=====
<em>Data
</em>
i = 2, because 1 mol of NaCl gives 2 mol of ions in solution.
Kb = 0.51 °C·mol·kg⁻¹
b = 1.00/0.155
b = 6.452 mol·kg⁻¹
=====
<em>Calculations
</em>
ΔTb = 2 × 0.51 × 6.452
ΔTb = 6.58°C
Tb = Tb° + ΔTb
Tb = 100 + 6.58
Tb = 106.6 °C
