No Solution:
4x+10y = 40
2x + 5y = 40
2x - 8y=17
x - 4y = 7
One Solution:
2y - X= 12
2y - 2x =10
x + 10y =50
2x + 10y =90
Infinitely Many Solutions:
x + 2y = 1
3x + 6y= 3
2y - 3x = 5
2/5y -3/5x =1
Explanation: You only had 11 equations listed. But I believe these are the ones you want. I took the test and got them right. Hope it helps
<u>Answers</u>
(a) 6.75 Joules.
(b) 5.27 m/s
(c) 0.75 Joules
<u>Explanation</u>
Kinetic energy is the energy possessed by a body in motion.
(a) its kinetic energy at A?
K.E = 1/2 mv²
= 1/2 × 0.54 × 5²
= 6.75 Joules.
(b) its speed at point B?
K.E = 1/2 mv²
7.5 = 1/2 × 0.54 × V²
V² = 7.5 ÷ 0.27
= 27.77778
V = √27.77778
= 5.27 m/s
(c) the total work done on the particle as it moves from A to B?
Work done = 7.5 - 6.75
= 0.75 Joules
Answer:
a) P = 149140[w]; b) 1491400[J]; c) v = 63.06[m/s]
Explanation:
As the solution to the problem indicates, we must convert the power unit from horsepower to kilowatts.
P = 200 [hp]
![200[hp] * 745.7 [\frac{watt}{1 hp}]\\149140[watt]](https://tex.z-dn.net/?f=200%5Bhp%5D%20%2A%20745.7%20%5B%5Cfrac%7Bwatt%7D%7B1%20hp%7D%5D%5C%5C149140%5Bwatt%5D)
Now the power definition is known as the amount of work done in a given time
P = w / t
where:
w = work [J]
t = time [s]
We have the time, and the power therefore we can calculate the work done.
w = P * t
w = 149140 * 10 = 1491400 [J]
And finally, we can calculate the velocity using, the expression for kinetic energy
![E_{k}=w=0.5*m*v^{2}\\ where:\\v = velocity[m/s]\\m=mass=750[kg]\\w=work=1491400[J]\\](https://tex.z-dn.net/?f=E_%7Bk%7D%3Dw%3D0.5%2Am%2Av%5E%7B2%7D%5C%5C%20%20where%3A%5C%5Cv%20%3D%20velocity%5Bm%2Fs%5D%5C%5Cm%3Dmass%3D750%5Bkg%5D%5C%5Cw%3Dwork%3D1491400%5BJ%5D%5C%5C)
The key to solving this problem is to recognize that work equals kinetic energy
![v=\sqrt{\frac{w}{0.5*m}} \\v=\sqrt{\frac{1491400}{0.5*750}} \\v=63.06[m/s]](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7Bw%7D%7B0.5%2Am%7D%7D%20%20%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B1491400%7D%7B0.5%2A750%7D%7D%20%20%5C%5Cv%3D63.06%5Bm%2Fs%5D)
Answer:
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Explanation:
Answer:
D. Humidity refers to the amount of water vapor in the air
