Answer:
1. The dilution factor for the serial dilution = 2
2. V2 = 1 mL
3. V1 = 0.5 mL
Explanation:
1. Dilution factor is the ratio of the initial concentration to the final concentration.
Dilution factor = initial concentration / final concentration
First dilution: initial concentration = 60 mg/dL
final concentration = 30 mg/dL
Dilution factor = 60 mg/dL / 30 mg/dL = 2
Second dilution: initial concentration = 30 mg/dL
final concentration = 15 mg/dL
Dilution factor = 30 mg/dL / 15 mg/dL = 2
Therefore, the dilution factor for the serial dilution = 2
2. From the dilution formula, C1V1 = C2V2; V2 = final volume to be prepared.
Since 1 mL of the various glucose solutions are to be prepared, the final concentration, V2 = 1 mL
3. From the dilution formula, C1V1 = C2V2; V1 = initial concentration of the solution to be prepared.
C1/C2 = V2/V1
Since the dilution factor, C1/C2 is 2, V2/V1 = 2
V1 = V2/2
V1 = 1 mL / 2
V1 = 0.5 mL
