Answer:
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The equation for density id D=M/V, which is density is equal to mass over volume. The mass (46.8 g) divided by the volume (6 cm^3), is the density. I calculated it to be 7.8 g/cm^3
Answer: E
How much NH₃ can be produced from the reaction below:
N₂ + 3H₂ - 2NH₃
The stoichiometric ratio of the reactants = 1:3
Given
74.2g of N₂, and Molar mass = 14g/mole
Mole of N₂ = 74.2/14=5.3mols of N₂,
and 14mols of H₂
From this given values and comparing with the stoichiometric ratio, H₂ will be the limiting reagent while N₂ is the excess reactant.
i.e, for every 14mols of H₂, we need 4.67mols of N₂ to react with it to produce 9.33mols of NH₃ as shown (vice versa)
From this we have 9.33mols of NH₃ produced
Avogadro constant, we have n = no of particles = 6.022x10²³ molecules contained in every mole of an element.
For a 9.33mols of NH3, we have 9.33x6.022x10²³molecules in NH3
5.62x10²⁴molecules of NH₃
Explanation:
H2So4=sulphuric acid , strong acid
Answer:
Linear combination of atomic orbitals (LCAO) is a simple method of quantum chemistry that yields a qualitative picture of the molecular orbitals (MOs) in a molecule. Let us consider H
+
2
again. The approximation embodied in the LCAO approach is based on the notion that when the two protons are very far apart, the electron in its ground state will be a 1s orbital of one of the protons. Of course, we do not know which one, so we end up with a Schrödinger cat-like state in which it has some probability to be on one or the other.
As with the HF method, we propose a guess of the true wave function for the electron
ψg(r)=CAψ
A
1s
(r)+CBψ
B
1s
(r)
where ψ
A
1s
(r)=ψ1s(r−RA) is a 1s hydrogen orbital centered on proton A and ψ
B
1s
(r)=ψ1s(r−RB) is a 1s hydrogen orbital centered on proton B. Recall ψ1s(r)=ψ100(r,ϕ,θ). The positions RA and RB are given simply by the vectors
RA=(0,0,R/2)RB=(0,0,−R/2)
The explicit forms of ψ
A
1s
(r) and ψ
B
1s
(r) are
ψ
A
1s
(r) =
1
(πa
3
0
)1/2
e−|r−RA|/a0 ψ
B
1s
(r) =
1
(πa
3
0
)1/2
e−|r−RB|/a0
Now, unlike the HF approach, in which we try to optimize the shape of the orbitals themselves, in the LCAO approach, the shape of the ψ1s orbital is already given. What we try to optimize here are the coefficients CA and CB that determine the amplitude for the electron to be found on proton A or proton B.
Explanation: