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goldenfox [79]
2 years ago
7

Help please!

Chemistry
1 answer:
Katyanochek1 [597]2 years ago
3 0

The observation, in this case, is quantitative.

<h3>Quantitative observation</h3>

Quantitative observations are observations that can be recorded based on quantitative data. In other words, they are observations that can be assigned numerical values.

Quantitative observations are as opposed to qualitative observations because the former cannot be assigned numerical values. They can be ranked or qualified.

In this case, Danielle and Heather could assign numbers to the length, width, and height of the tank in order to calculate its volume.

More on quantitative observations can be found here: brainly.com/question/17491501

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How many g of MgCO3(s) are needed to make 1.2 L of 1.5 M MgCl2(aq) solution?
maw [93]
Molar mass of MgCO3 is 84.313 g/mol
You can calculate this from data on the periodic table:
Molar mass Mg = 24.305g/mol
molar mass C = 12.011g/mol
molar mass O = 15.999g/mol mass 3 mol = 47.997g
Total = 84.313g/mol

Mass to be used in 1.2L of 1.5M solution = 84.313g * 1.2L * 1.5mol /L = 151.763g
I have not taken significant figures into account
The balanced equation you provide is not necessary in this calculation
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