Volume of the cube with side 4p = 4p x 4p x 4p = 64p³

Volume of the cube with side 2q² =  2q² x  2q² x  2q² = 8q⁶

Total Volume = 64p³ +  8q⁶

Total Volume = (4p)³ + (2q²)³

Total Volume = (4p + 2q²)( ( 4p)² - (4p)(2q²) + (2q²)²)

Total Volume = (4p + 2q²)( 16p² - 8pq² + 4q⁴)

Answer:  (4p + 2q²)( 16p² - 8pq² + 4q⁴)

7 0

3 years ago

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The diameter of a sphere is 21.6 cm. What is the sphere's volume? Round to the nearest tenth, if necessary.

NeX [460]

By definition, the volume of a sphere is:
$V = \frac{4}{3} (\pi) (r ^ 3)
$
Where,
r: sphere radio
Substituting values we have:
$V = \frac{4}{3}(3.14)(( \frac{21.6}{2} ) ^ 3)
$
$V = 5273.99424
$ Rounding the result to the nearest tenth:
$V = 5274.0 cm ^ 3
$ Answer:
the sphere's volume is:
$V = 5274.0 cm ^ 3$

5 0

3 years ago