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miss Akunina [59]
4 years ago
12

Supplies, clutter and __________ are two common tripping hazards in a shop environment.

Engineering
1 answer:
Andreyy894 years ago
6 0

Answer:

The correct option is;

Loose cords

Explanation:

Based on the 2011 Census of Occupational Injuries, which is published by the Bureau of Labor Statistics, one of the leading causes of injuries at work is slips, trips and falls which may lead long duration of time down and large huge amount of claims for compensation. Slips trips and falls are also comes fourth in the reasons of fatality at work

Trip hazards are hazards that causes trip and fall by stopping and locking the movement of the step of people walking along traffic lanes

Items that cause trips mainly include item used for work. The correct option is therefore loose cords, which should be kept under cable bridges for safety.

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The ???? − i relationship for an electromagnetic system is given by ???? = 1.2i1/2 g where g is the air-gap length. For current
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Answer:

a) The mechanical force is -226.2 N

b) Using the coenergy the mechanical force is -226.2 N

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a) Energy of the system:

\lambda =\frac{1.2*i^{1/2} }{g} \\i=(\frac{\lambda g}{1.2} )^{2}

\frac{\delta w_{f} }{\delta g} =\frac{g^{2}\lambda ^{3}  }{3*1.2^{2} }

f_{m}=- \frac{\delta w_{f} }{\delta g} =-\frac{g^{2}\lambda ^{3}  }{3*1.2^{2} }

If i = 2A and g = 10 cm

\lambda =\frac{1.2*i^{1/2} }{g} =\frac{1.2*2^{1/2} }{10x10^{-2} } =16.97

f_{m}=-\frac{g^{2}\lambda ^{3}  }{3*1.2^{2} }=-\frac{16.97^{3}*2*0.1 }{3*1.2^{2} } =-226.2N

b) Using the coenergy of the system:

f_{m}=- \frac{\delta w_{f} }{\delta g} =-\frac{1.2*2*i^{3/2}  }{3*g^{2} }=-\frac{1.2*2*2^{3/2} }{3*0.1^{2} } =-226.2N

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A.

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Answer:

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3rd and 4rth

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a geologist studies the earth and both of these have something to do with the earth

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