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aivan3 [116]
3 years ago
9

2x²-6x+10/x-2 x=2plsssss​

Engineering
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

hope it helps you..

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Base course aggregate has a target dry density of 119.7 lb/cu ft in place. It will be laid down and compacted in a rectangular s
natita [175]

Answer:

total weight of aggregate =  5627528 lbs = 2814 tons  

Explanation:

given data

dry density = 119.7 lb/cu ft

area = 2000 ft × 48 ft × 6 in

aggregate = 3.1%

required compaction = 95%

solution

we get  here volume of space to be filled with aggregate that is

volume = 2000 × 48 × 0.5 = 48000 ft³

when here space fill with aggregate of density is

density = 0.95 × 119.7    = 113.72 lb/ft³

and

dry weight of this aggregate will be  is

dry weight = 48000 × 113.72 = 5458320 lbs

and

we consider take percent moisture by weigh so that there weight of moisture in aggregate is express as

weight of moisture = 0.031 × 5458320 = 169208 lbs

and

total weight of aggregate will be

total weight of aggregate = 5458320 + 169208

total weight of aggregate =  5627528 lbs = 2814 tons  

5 0
3 years ago
List three types of concurrent engineering in manufacturing.
klio [65]

Answer:

A famous example of concurrent engineering is the development of the Boeing 777 commercial aircraft. The aircraft was designed and built by geographically distributed companies that worked entirely on a common product database of C A TIA without building physical mock-ups but with digital product definitions.

8 0
3 years ago
A piece of corroded steel plate was found in a submerged ocean vessel. It was estimated that the original area of the plate was
shepuryov [24]

Answer:

Time of submersion in years = 7.71 years

Explanation:

Area of plate (A)= 16in²

Mass corroded away = Weight Loss (W) = 3.2 kg = 3.2 x 106

Corrosion Penetration Rate (CPR) = 200mpy

Density of steel (D) = 7.9g/cm³

Constant = 534

The expression for the corrosion penetration rate is

Corrosion Penetration Rate = Constant x Total Weight Loss/Time taken for Weight Loss x Exposed Surface Area x Density of the Metal

Re- arrange the equation for time taken

T = k x W/ A x CPR x D

T = (534 x 3.2 x 106)/(16 x 7.9 x 200)

T = 67594.93 hours

Convert hours into years by

T = 67594.93 x (1year/365 days x 24 hours x 1 day)

T = 7.71 years

3 0
4 years ago
Sedimentary rock forms at or near the
Natalija [7]
I believe it’s A bit I. could be wrong
5 0
3 years ago
Read 2 more answers
A material with a yield strength of 40 kpsi and an endurance strength of 20 kpsi is intended for an application with a von Mises
wlad13 [49]

To solve this problem we will apply the concepts related to Soderberg's relation, which will allow us to find the safety factor based on yield stress, endurance strength, the mean and average stress. The mean and average stress values can be found through the alternating Stress previously given. We will proceed by defining the known values, that is

Yield stress \sigma_y = 40ksi

Endurance strength \sigma_e = 20ksi

The two values for alternating stress are

\sigma_1 = 17ksi

\sigma_2 = 3ksi

We know that mean stress is

\sigma_m = \frac{\sigma_1+\sigma_2}{2}

\sigma_m = \frac{17+3}{2} = 10ksi

And the average stress is

\sigma_v = \frac{\sigma_1-\sigma_2}{2}

\sigma_v = \frac{17-3}{2} = 7ksi

According to Soderberg relation

\frac{1}{F.s} = \frac{\sigma_m}{\sigma_y}+\frac{\sigma_v}{\sigma_e}

\frac{1}{F.s} = \frac{10}{40}+\frac{7}{20}

\frac{1}{F.s} = 0.6

F.s = 1.66 \approx 2

Therefore the factor of safety is 2

3 0
3 years ago
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