Two advantages of deforming steel at room temperature rather than at elevated temperatures are: (select 2 answers from the optio
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Since the armature is wave wound, the magnetic flux per pole is 0.0274 Weber.
<u>Given the following data:</u>
- Emf = 520 Volts
- Speed = 660 r.p.m
- Number of armature conductors = 144 slots
- Number of poles = 4 poles
- Number of parallel paths = 2
To find the magnetic flux per pole:
Mathematically, the emf generated by a DC generator is given by the formula;
×
<u>Where:</u>
- E is the electromotive force in the DC generator.
- Z is the total number of armature conductors.
- N is the speed or armature rotation in r.p.m.
- P is the number of poles.
- A is the number of parallel paths in armature.
- Ф is the magnetic flux.
First of all, we would determine the total number of armature conductors:
×
×
Z = 864
Substituting the given parameters into the formula, we have;
×
×
<em>Magnetic flux </em><em>=</em><em> 0.0274 Weber.</em>
Therefore, the magnetic flux per pole is 0.0274 Weber.
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Answer:
a. V = 109.64 × 10⁵ ft/min
b. Mw = 654519.54 kg/hr
Explanation:
Given Parameters
mass flow rate of water, Mw = 90000g/min = 6607.33 kg/s
inlet temperature of water, T1 = 84 F = 28.89 C
outlet temperature of water, T2 = 68 F = 20 C
specific heat capacity of water, c = 4.18kJ/kgK
rate of heat remover from water, Qw is given by
Qw = 6607.33[28.89 - 20] * 4.18
Qw = 245529.545kw
For air, inlet condition
DBT = 70 F hi = 43.43 kJ/kg
WBT = 60 F wi = 0.00874 kJ/kg
u1 = 0.8445 m/kg
oulet condition,
DBT = 70 F RH = 100.1
h1 = 83.504kJ/kg
Wo = 0.222kJ/kg
check the attached file for complete solution
