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Sergeeva-Olga [200]
2 years ago
13

Two advantages of deforming steel at room temperature rather than at elevated temperatures are: (select 2 answers from the optio

ns below)
A. better dimensional accuracy

B. elimination of coring by diffusion

C. a smoother surface finish

D. less energy is required
Engineering
1 answer:
Aleks [24]2 years ago
7 0

Answer:

A AND C

Explanation:

Two advantages of deforming steel at room temperature rather than at elevated temperatures are: (select 2 answers from the options below)

A. better dimensional accuracy to allow form complex parts with complex geometries.

C. a smoother surface finish to allow elimination of finish machining and grinding operations.

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A 10.2 mm diameter steel circular rod is subjected to a tensile load that reduces its cross- sectional area to 52.7 mm^2. Determ
VMariaS [17]

Answer:

The percentage ductility is 35.5%.

Explanation:

Ductility is the ability of being deform under applied load. Ductility can measure by percentage elongation and percentage reduction in area. Here, percentage reduction in area method is taken to measure the ductility.

Step1

Given:

Diameter of shaft is 10.2 mm.

Final area of the shaft is 52.7 mm².

Calculation:

Step2

Initial area is calculated as follows:

A=\frac{\pi d^{2}}{4}

A=\frac{\pi\times(10.2)^{2}}{4}

A = 81.713 mm².

Step3

Percentage ductility is calculated as follows:

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5 0
2 years ago
A circular specimen of MgO is loaded in three-point bending. Calculate the minimum possible radius of the specimen without fract
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Answer:

radius = 9.1 × 10^{-3} m

Explanation:

given data

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solution

we apply here minimum radius formula that is

radius = \sqrt[3]{\frac{FL}{\sigma \pi}}      .................1

here F is applied load and  is length

put here value and we get

radius =  \sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}  

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