Answer:
Mass of phosphoric acid = 6.37 g
Mass of magnesium nitride = 50.5 g
Mass of iron chloride = 22.71 g
Explanation:
1 = Given data:
Mass of phosphorus = 4 g
Mass of phosphoric oxide = ?
Solution:
4P + 5O₂ → 2P₂O₅
Number of moles of phosphorus = mass / molar mass
Number of moles of phosphorus = 4 g / 31 g/mol
Number of moles of phosphorus = 0.13 mol
Mole ration of phosphorus and phosphoric acid.
P : P₂O₅
4 : 2
0.13 : 2/4× 0.13 = 0.065 mol
Mass of phosphoric acid:
Mass of phosphoric acid = moles × molar mass
Mass of phosphoric acid = 0.065 mol × 98 g/mol
Mass of phosphoric acid = 6.37 g
2 = Given data:
Mass of magnesium = 36 g
Mass of magnesium nitride = ?
Solution:
3Mg + N₂ → Mg₃N₂
Number of moles of magnesium = mass / molar mass
Number of moles of magnesium = 36 g / 24 g/mol
Number of moles of magnesium = 1.5 mol
Mole ration of magnesium and magnesium nitride.
Mg : Mg₃N₂
3 : 1
1.5 : 1/3× 1.5 = 0.5 mol
Mass of magnesium nitride:
Mass of magnesium nitride = moles × molar mass
Mass of magnesium nitride = 0.5 mol × 101 g/mol
Mass of magnesium nitride = 50.5 g
3 = Given data:
Mass of iron = 8 g
Mass of iron chloride = ?
Solution:
2Fe + 3Cl₂ → 2FeCl₃
Number of moles of iron = mass / molar mass
Number of moles of iron = 8 g / 55.85 g/mol
Number of moles of iron = 0.14 mol
Mole ration of iron and iron chloride.
Fe : FeCl₃
2 : 2
0.14 : 0.14
Mass of iron chloride:
Mass of iron chloride = moles × molar mass
Mass of iron chloride = 0.14 mol × 162.2 g/mol
Mass of iron chloride = 22.71 g
