Answer:
<span>D) combine light nuclei
</span>
Explanation:
Fission and fusion both deal with the alteration of atoms in order to produce energy. However, they are actually opposite processes, this is because:
1- Fission occurs when an atomic nucleus is split/divided into two forming two atoms
2- Fusion occurs when two light atomic nuclei combine together to form a single atom.
Hope this helps :)
4C₃H₅(NO₃)₃
------> 12CO₂
+ 6N₂
+ 10H₂O
+ O₂![_{(g)}](https://tex.z-dn.net/?f=_%7B%28g%29%7D%20)
mol of CO₂ = ![\frac{mass}{molar mass}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D%20)
= ![\frac{25g}{44.01 g/mol}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25g%7D%7B44.01%20g%2Fmol%7D%20)
mol ratio of CO₂ : C₃H₅(NO₃)₃
12 : 4
∴ if mole of CO₂ = 0.568 mol
then " " C₃H₅(NO₃)₃ = ![\frac{0.568 mol}{12} * 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B0.568%20mol%7D%7B12%7D%20%20%2A%20%204)
= 0.189 mol
∴ mass of nitroglycerin = mole * Mr
= 0.189 mol * 227.0995 g / mol
= 43.00 g
Answer:
D. Anti-periplanar
Explanation:
In the <u>second step</u> of the intramolecular William Ether Synthesis mechanism (figure 1) we will have the attack of the negative charge of the oxygen to the carbon bond to the Br. At the same time the Br leaves, so a bond would be broken (the <u>C-Br</u> bond) and a bond would be formed (the <u>C-O</u> bond).
Now, this process can happen only if the <u>attack</u> and the <u>leaving group </u>has an anti configuration (figure 2). In an anti configuration the <u>nucleophile</u> and the <u>leaving group</u> would have <u>opposite directions</u>.
I’m not forsure but I’m thinking it’s c sorry if I’m wrong
Answer:
0.231 mol/L
Explanation:
The first step is to write the balanced equation for this reaction:
![H_{2}SO_{4} +2NaOH ===> Na_{2}SO_{4} +2H_{2}O](https://tex.z-dn.net/?f=H_%7B2%7DSO_%7B4%7D%20%2B2NaOH%20%3D%3D%3D%3E%20Na_%7B2%7DSO_%7B4%7D%20%20%2B2H_%7B2%7DO)
The second step is to find the number of moles in the acid:
number of moles = volume * concentration
= 0.035 L * 0.275 mol/L
= 0.009625 mol
The third step is to use the molar ratio from the balanced chemical equation to find the number of moles of NaOH that can neutralize 0.009625 mol of sulphuric acid.
n(sulphuric acid) : n(sodium hydroxide)
1 : 2
0.009625 mol : x
x = 0.01925 mol
Fourth step is to calculate the concentration of sodium hydroxide:
![concentration = \frac{number of moles}{volume} = \frac{0.01925}{0.0835} =0.231 mol/L](https://tex.z-dn.net/?f=concentration%20%3D%20%5Cfrac%7Bnumber%20of%20moles%7D%7Bvolume%7D%20%3D%20%5Cfrac%7B0.01925%7D%7B0.0835%7D%20%3D0.231%20mol%2FL)