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STatiana [176]
3 years ago
12

The first measurements of the sea depth was made in 1840 in the centra south of Atlantic, where a plummet was lowered 2425 fatho

ms. What is the depth in meters? Note 1 fathom=6ft, 1ft=12in, 1ft=2.54*10
Chemistry
1 answer:
larisa [96]3 years ago
4 0

Answer:

4435 m  

Explanation:

1. Number of feet

\text{No. of feet} = \text{2425 fathoms} \times \dfrac{\text{6 ft}}{\text{1 fathom}} = \text{14 550 ft}

2. Number of inches  

\text{No. of inches} = \text{14 550 ft} \times \dfrac{\text{12 in}}{\text{1 ft}} =\text{174 600 in}

3. No. of centimetres

\text{No. of centimetres} = \text{174 600 in} \times \dfrac{\text{1 cm}}{\text{2.54 in}} = \text{443 500 cm}

4. No. of metres

\text{No. of metres} = \text{443 500 cm} \times \dfrac{\text{1 m}}{\text{100 cm}} = \textbf{4435 m}

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Help plssssssssssssssss??
ser-zykov [4K]

Answer:

Chemical properties, such as combustibility, are generally observed as the identity of a substance changes and one or more new substances form.

Explanation:

Chemical change involves formation of new substances. Therefore, the correct answer is "Chemical properties, such as combustibility, are generally observed as the identity of a substance changes and one or more new substances form."

8 0
2 years ago
6. A solution of CuSO4 is electrolyzed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the
vladimir2022 [97]

The mass of Copper deposited at the cathode : 0.296 g

<h3>Further explanation</h3>

Given

time = t = 10 min=600 s

current = i = 1.5 A

F = 96500 C

charge Cu=+2

Required

The mass of Copper

Solution

Faraday's Law

\tt W=\dfrac{e.i.t}{96500}

e = Ar/valence(valence Cu=2, Ar=63.5 g/mol)

Input the value :

\tt W=\dfrac{63.5/2\times 1.5\times 600}{96500}\\\\W=0.296~g

5 0
3 years ago
What happens to the atomic radius when an elctron is lost​
Daniel [21]

Answer:

It decreases.

Explanation:

Due to changes in the Coulombic force, the protons within the nucleus of the ion have a much easier time pulling at one fewer electrons. This way, the electrons are pulled closer to the center, causing the radius to decrease.

5 0
3 years ago
4. How many grams are in 54 moles H,O?
Marrrta [24]

Answer:

Explanation:1.8

×

10

24

 water molecules.

Explanation:

There are  

6.022

×

10

23

molecules in a mole.

There are  

18.01528

grams of water per mole of water.

These can be figured out using the concept of moles and molecular weight. I have attached a video that provides a good explanation.

Explanation of moles and molecular weight

Now you have all the information needed to solve the problem.

You start out with 54 grams of water. You want to convert that into molecules, but how can you do that? You can't go directly from grams to molecules because there is no easy unit conversion. However, you can go from grams to moles using

18.01528

grams of water per mole of water.

From there, you can go from moles to molecules using  

6.022

×

10

23

molecules in a mole.

A T chart is useful for this kind of problem.

54 g H

2

O

×

1 mol  H

2

O

18.0152 g H

2

O

×

6.022

×

10

23

 

molecules

1 mol H

2

O

54

g H

2

O

×

1 mol  H

2

O

18.0152

g H

2

O

×

6.022

×

10

23

 

molecules

1 mol H

2

O

Notice when you apply this T chart, the units cancel out, leaving molecules in the final answer, which is the correct units.

Now actually multiply everything out

54

×

6.022

×

10

23

18.0152

=

1.805

×

10

24

You are left with  

1.8

×

10

24

water molecules (rounded to two sig figs).

8 0
3 years ago
Read 2 more answers
. Explain why, in the sample calculations, 0.1 g of the unknown produced a GREATER freezing point depression than~e same mass of
dimulka [17.4K]

Answer

Naphthalene is a non electrolyte

If the unknown compound is an electrolyte it gives 2 or more ions in solution

( NaCl >> Na+ + Cl- => 2 ions

Ca(NO3)2 >> Ca2+ + 2 NO3- => 3 ions)

the f.p. lowering is directly proportional to the molal concentration of dissolved ions in the solution )

For naphthalene

delta T = 1.86 x m

for a salt that gives 2 ions

delta T = 1.86 x m x 2

hence the lowering in freezion point of unkown is greater then napthalene

6 0
3 years ago
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