Answer:
11.3298W
Explanation:
The rate of heat transfer is determined from the enthalpy of vaporization at the give pressure obtained and the mass flow rate. The mass flow rate is determined from the volume of the boiled water, the given time interval and the specific volume of the saturated liquid.
Given that
1atm as the atmospheric pressure
Internal diameter = 20cm = 0.2m
Time = 15mins = (15×60)secs
Latent heat of vaporization (hevap) = 2256.6
Q = mh(evap)
= m/∆t . hevap
= V/αliq∆t ×h(evap)
D^2π∆h/4αliq ∆t × hevap
= 0.2^2 ×π×0.8×2256.5/4×0.001043×15×60
=0.04×3.142×0.08×2256.6/2.00256
= 22.68876/2.00256
Q = 11.3298W
Answer:
Whats The Question Exactly (Ill Edit This To Fit It)
Explanation:
ANSWER
![B. 40.6\degree](https://tex.z-dn.net/?f=B.%2040.6%5Cdegree)
EXPLANATION
A sketch of the vector is shown in the diagram in the attachment.
The side adjacent to the angle we want to find is 3.5 units and the opposite side is 3 units.
Let the angle between the vector and the x-axis be ![\phi](https://tex.z-dn.net/?f=%5Cphi)
then,
![\tan\phi =\frac{3}{3.5}](https://tex.z-dn.net/?f=%5Ctan%5Cphi%20%3D%5Cfrac%7B3%7D%7B3.5%7D)
![\tan\phi=0.8571](https://tex.z-dn.net/?f=%5Ctan%5Cphi%3D0.8571)
This implies that,
![\phi=tan{-1}(0.8571)](https://tex.z-dn.net/?f=%5Cphi%3Dtan%7B-1%7D%280.8571%29)
![\phi=40.6013](https://tex.z-dn.net/?f=%5Cphi%3D40.6013)
The correct answer is B
Therefore the angle 40.6° to the nearest tenth.
Answer:
The final temperature is T2= 5.35°C
Explanation:
Apply the Gay-lussacs's law we have
![\frac{P1}{T1} = \frac{P2}{T2}](https://tex.z-dn.net/?f=%5Cfrac%7BP1%7D%7BT1%7D%20%3D%20%5Cfrac%7BP2%7D%7BT2%7D)
P1, initial pressure= 5.00 x 10^6 Pa
T1, initiation temperature= 25.°C
P2, final pressure= 1.07 x 10^6 Pa
T2, final temperature= ?
![\frac{5.00 * 10^6}{25} =\frac{1.07 *10^6}{T2} \\](https://tex.z-dn.net/?f=%5Cfrac%7B5.00%20%2A%2010%5E6%7D%7B25%7D%20%3D%5Cfrac%7B1.07%20%2A10%5E6%7D%7BT2%7D%20%5C%5C)
Cross multiplying and making T2 subject of formula we have
![T2 =\frac{1.07 *10^6*25}{5.00 * 10^6} \\\\T2= \frac{26.75}{5} \\T2= 5.35](https://tex.z-dn.net/?f=T2%20%3D%5Cfrac%7B1.07%20%2A10%5E6%2A25%7D%7B5.00%20%2A%2010%5E6%7D%20%5C%5C%5C%5CT2%3D%20%5Cfrac%7B26.75%7D%7B5%7D%20%5C%5CT2%3D%205.35)
T2= 5.35°C
Answer:
19
Explanation:
I legit did this and it took 19.