Octet law states that every atom tries to attain a octet valence shell (8 electrons in their valence shell) to attain a more stable state. For attaining this they form bonds(covalent,ionic etc) with other atoms. Please ask if you any more doubt on this, I'll try to help
CH4+2O2–> CO2+2H2O
-count the number of atoms of each element on each side of the reaction arrow, there is 1 carbon,4 hydrogen, and 2 oxygen on the reactant side and 1 carbon, 2 hydrogen, and 3 oxygen on the product side.Then add coefficients so the number of atoms of each element is the same on both sides of the equation
(a) In this section, give your answers to three decimal places.
(i)
Calculate the mass of carbon present in 0.352 g of CO
2
.
Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g
of
A
.
(ii)
Calculate the mass of hydrogen present in 0.144 g of H
2
O.
Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g
of
A
.
(iii)
Use your answers to calculate the mass of oxygen present in 0.240 g of
A
Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g
of
A
(b)
Use your answers to
(a)
to calculate the empirical formula of
A
thank you
hope it helpsss
Given
Mass of NO - 824 g
Molar mass of NO - 30.01g/mol
No of moles of NO = Given mass/Molar mass
No of moles of NO = 824/30.01= 27.45 mole
Hence 27.5 moles of NO are formed!
1 mole C₆H₁₂O₆ ------------- 6 moles oxygen
3 moles <span>C₆H₁₂O₆ ----------- X
X = (3</span>×6)/1
<u>X = 18 moles</u>
:)
