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jek_recluse [69]
2 years ago
6

HOW DOES DENSITY AFFECT THE MELTING POINT OF WATER?

Chemistry
1 answer:
ddd [48]2 years ago
5 0
<span> As a liquid is heated, its vapor pressure increases until the vapor pressure equals the pressure of the gas above it. Bubbles of vaporized liquid (i.e., gas) form within the bulk liquid and then rise to the surface where they burst and release the gas. (At the boiling temperature the vapor inside a bubble has enough pressure to keep the bubble from collapsing.) In order to form vapor, the molecules of the liquid must overcome the forces of attraction between them.<span> The temperature of a boiling liquid remains constant, even when more heat is add.</span></span>
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3 Apply Use context clues to write your own definitions for the words definite and occupy.
motikmotik

Answer:

Explanation:

own definitions for the words definite and occupy.

Example sentence

Solid is the state of matter that has a definite shape and volume.

definite:

__________

Example sentence

A larger container will allow a gas to occupy more space.

occupy:

3 0
1 year ago
What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
Ymorist [56]

Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}

Thus, it is possible to find x given the pH as shown below:

x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M

So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

Best regards!

6 0
2 years ago
Help someone!!!I will mark you brainliest
iVinArrow [24]
A) Na2S
b) AlF3
c) O2
d) C6H12O6
4 0
2 years ago
Read 2 more answers
At constant pressure, how are the temperature and volume of a gas related?
RideAnS [48]

Answer:

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).

4 0
2 years ago
What is the molarity of a solution that contains 0.082 mol KI in a 2.03 L solution?
astraxan [27]

Answer:

molarity of the KI solution = 0.04 mol/L

Explanation:

Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution.  

The law that we can applied to calculate the M is:  

M = n / V

n - number of moles

V- volume of the solution (liters)

Then insert in the equation the values from the question;  

M = 0.082 mol  /  2.03 L = 0.04 mol/L

4 0
3 years ago
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