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trapecia [35]
2 years ago
14

1. Given the following equation:

Chemistry
1 answer:
Delvig [45]2 years ago
5 0

The percent yield obtained from the stoichiometry of the reaction when the moles of the reactants and products are known.

<h3>What is stoichiometry?</h3>

Stochiometry gives the relationship between the mass and mole or moles and volume in a reaction.

Q1)

K2PtCl4 + 2NH3 ----> Pt(NH3)2Cl2 +2KCl

Number of moles of NH3 = 34.5 g/17 g/mol = 2.03 moles

2 moles of NH3 yields 2 moles of KCl

2.03 moles  of NH3 yields 2.03 moles  of KCl

Theoretical yield of KCl =  2.03 moles * 75 g/mol = 154 g

Again,

2moles of NH3 yields 1 mole of Pt(NH3)2Cl2

2.03 moles  of NH3 yields 2.03 moles  * 1/2 = 1.015 moles

Mass of Pt(NH3)2Cl2 = 1.015 moles * 301 g/mol = 306 g

% yield =  76.4 g/306 g * 100/1 = 25%

Q2)

H3PO4 + 3 KOH ------> K3PO4 + 3 H2O

Number of moles of H3PO4  = 49.0 g/98 g/mol = 0.5 moles

If  mole of H3PO4  yield 1 mole of K3PO4

0.5 moles of H3PO4  yield 0.5 moles of K3PO4

Mass of K3PO4  = 212 g/mol * 0.5 moles = 106 g

Percent yield = 49.0 g/106 g * 100 = 46%

Q3)

Al2(SO3)3 + 6 NaOH ------> 3 Na2SO3 + 2 Al(OH)3

Number of moles of Al2(SO3)3 = 389.4 g/294 g/mol = 1.32 moles

If 1 mole of Al2(SO3)3 yields 3 moles of  Na2SO3

1.32 moles of Al2(SO3)3 yields 1.32 moles  * 3 moles/1 mole = 3.96 moles

Mass of Na2SO3 = 3.96 moles * 126 g/mol = 498.96 g

Percent yield = 212.4 g/498.96 g * 100/1 = 43%

Q4)

Al(OH)3(s) + 3 HCl(aq) -------> AlCl3(aq) + 3 H2O(l)

Number of moles of Al(OH)3 = 50.3 g/78 g/mol = 0.64 moles

If 1 mole of Al(OH)3 yields 1 mole of AlCl3

0.64 moles of Al(OH)3 yields 0.64 moles of AlCl3

Mass of AlCl3 = 133 g/mol * 0.64 moles = 85 g

Percent yield = 39.5 g/85 g * 100 = 46%

Q5) K2CO3 + 2HCl --------> H2O + CO2 + 2KCl

Number of moles of K2CO3 = 34.5 g/138 g/mol = 0.25 moles

1 mole of K2CO3  produces 2 moles of KCl

0.25 moles of K2CO3  produces 0.25 moles * 2 moles/1 mole = 0.5 moles

Mass of KCl = 0.5 moles * 75 g/mol = 37.5 g

If 1 mole of K2CO3  yields 1 mole of H2O

0.25 moles of K2CO3  yields 0.25 moles of H2O

Mass of H2O = 0.25 moles  * 18 g/mol = 4.5 g

Percent yield = 3.4 g/4.5 g *100 = 76%

Learn more about percent yield: brainly.com/question/12704041?

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