The key is in "they lock together". This tells you this is a complete inelastic collision and therefore you can use the formula:
m1*v1+m2*v2=v(m1+m2)
Plug in numbers:
2000*3+2000*2=v(2000+2000)
so v=2 m/s, obviously in the same direction of motion in which they were both moving.
Answer:
Yes, this is according to the Newton's first law of motion.
Neither its direction nor its velocity changes during this course of motion.
Explanation:
Yes, it is very well in accordance with Newton's first law of motion for a body with no force acting on it and it travels with a non-zero velocity.
During such a condition the object will have a constant velocity in a certain direction throughout its motion. Neither its direction nor its velocity changes during this course of motion.
It must be boiled/heated to a high temp
I think the answer is c but I'm not sure
By conservation of linear amount of movement, we have to
p1 = p2
Where, p = m * v.
So, using the definition for this case, we have:
(2.9 kg)•(26 cm/s) = (2.1 kg + 2.9 kg)•v
75.4 kg•cm/s = (5.0 kg)•v
v = 15.1 cm/s
