All categories

3 years ago

A bus starts from rest with the velocity 150 m/s in 20 seconds. Calculate its acceleration.

Physics

1 answer:

katen-ka-za [31]3 years ago

3 0

Answer:

7.5

Explanation:

Velocity÷time

You might be interested in

A carpenter builds an exterior house wall with a layer of wood 3.0 cm thick on the outside and a layer of Styrofoam insulation 2

Leno4ka [110]

Answer:

A. T=15.54 °C

B. Q/A= 0.119 W/m2

Explanation:

To solve this problem we need to use the Fourier's law for thermal conduction:

$Q= kA\frac{dT}{dx}$

Here, the rate of flow per square meter must be the same through the complete wall. Therefore, we can use it to find the temperature at the plane where the wood meets the Styrofoam as follows:

$\frac{Q}{A} =\frac{T_1-T_0}{d_w}k_w=\frac{T_2-T_1}{d_s}k_s\\T_1(\frac{k_w}{d_w}+\frac{k_s}{d_s})=T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}\\T_1=\frac{T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}}{\frac{k_w}{d_w}+\frac{k_s}{d_s}}\\T_1= 15.54 \°C$

Then, to find the rate of heat flow per square meter, we have:

$\frac{Q}{A}=\frac{T_1-T_0}{d_w}k_w=0.119 \frac{W}{m^2}\\\frac{Q}{A}=\frac{T_2-T_1}{d_s}k_s= 0.119 \frac{W}{m^2}$

$T_0: Temperature \ in \ the \ house\\T_1: Temperature \ at \ the \ plane \ between \ wood \ and \ styrofoam\\T_2: Temperature \ outside\\k_w: k \ for \ wood\\d_w: wood \ thickness\\k_s: k \ for \ styrofoam\\d_s: styrofoam \ thickness$

7 0

3 years ago

For a standard production car, the highest roadtested acceleration ever reported occurred in 1993, when a Ford RS200 Evolution w

Sidana [21]

Answer:

a=8.1832m/s^2

Explanation:

Vo=initial speed=0m/s

Vf=final speed=26.8m/s

t=time=3.275s

the vehicle moves with a constant acceleration therefore we can use the following equation

A=aceleration=(Vf-Vi)/t

A=(26.8m/s-0m/s)/3.275s=8.1832m/s^2

the magnitude of the car´s aceleration is 8.1832m/s^2

6 0

3 years ago

3V battery is used with a 15 ohm resistance.What is the current?

Pavlova-9 [17]

Answer:

0.2 A

Explanation:

V= IR

3 = I × 15

I = 3/15

= 1/5 = 0.2 A

5 0

3 years ago

si tienes 2 circuitos uno en serie y otro en paralelo con el mismo valor en sus resistencias, para cuál circuito la resistencia

Novosadov [1.4K]

Answer:

circuito paralelo

Explanation:

Siempre el circuito en paralelo dara una resistencia menor. Recuerda que las resistencias se suman en el circuito en serie, an cambio en el circuito en paralelo, la corriente se bifurca de manera de circular con mayor intensidad por las ramas que tengan menos resistencia, y tal situacion llevara siempre a producir una menor resistencia equivalente.

5 0

3 years ago

You are asked to help design a new type of loop-the-loop ride. Instead of rolling down a long hill to generate the speed to go a

Trava [24]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

5 0

4 years ago