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Sergeu [11.5K]
4 years ago
5

State Hund's rule.

Chemistry
1 answer:
loris [4]4 years ago
6 0

Answer:

C. The lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, all of which have the same spin, in degenerate orbitals.

Explanation:

The Hund's rule is used to place the electrons in the orbitals is it states that:

1. Every orbital in a sublevel is singly occupied before any orbital is doubly occupied;

2. All of the electrons in singly occupied orbitals have the same spin.

So, the electrons first seek to fill the orbitals with the same energy (degenerate orbitals) before paring with electrons in a half-filled orbital. Orbitals doubly occupied have greater energy, so the lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, and for the second statement, they have the same spin.

The other alternatives are correct, but they're not observed by the Hund's rule.

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A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure.
daser333 [38]

Answer:

1.429 g of  N₂

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The Haber process is a reaction that combines nitrogen with hydrogen to form ammonia according to the following balanced equation:

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We cannot compare weight of a substance (in grams) to another in chemical reactions, but we can use moles, then we have to convert the weight of NH3 to moles.

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and the actual yield is 98% , then the theoretical number of moles that would be produced are:  

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1 mol of N₂ → 2 mol of NH₃.

?? mol of N₂ → 0.102 mol of NH₃.

no of moles of N₂ = [(1 mol * 0.102 mol) / 2 mol] = 0.051 mol

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