Answer:
<h3><u>
Saturated and unsaturated</u>
:-</h3>
Are a form of fat in which all or most of the fatty acid chains are single bonds. Glycerol and fatty acids are the two types of smaller molecules that make up fat.
<h3>
<u>Saturated fat is found in:</u></h3>
<h3>
<u>Examples of unsaturated fats:- </u></h3>
- Olive
- Nuts(almonds, hazelnuts)
- Seeds(pumpkin and sesame seeds)
hope it helps...
Answer:
is a class of heavy military ranged weapons built to launch munitions far beyond the range and power of infantry firearms. This development continues today; modern self-propelled artillery vehicles are highly mobile weapons of great versatility generally providing the largest share of an army's total firepower.
Explanation:
it could explode
Naproxen is known to be a weak acid. In order to calculate
its ka and pka, use the equation of getting the ph of weak acid which is ph=
-1/2 log [(Ka)(Mwa)]. The Ka value is 3.18x10^-5. The pKa can be obtained
through pKa = - log Ka. The pKa is 4.5.
Answer:
588.2 mL
Explanation:
- FeSO₄(aq) + 2KOH(aq) → Fe(OH)₂(s) + K₂SO₄(aq)
First we <u>calculate how many Fe⁺² moles reacted</u>, using the given <em>concentration and volume of FeSO₄ solution</em> (the number of FeSO₄ moles is equal to the number of Fe⁺² moles):
- moles = molarity * volume
- 187 mL * 0.692 M = 129.404 mmol Fe⁺²
Then we convert Fe⁺² moles to KOH moles, using the stoichiometric ratios:
- 129.404 mmol Fe⁺² *
= 258.808 mmol KOH
Finally we<u> calculate the required volume of KOH solution</u>, using <em>the given concentration and the calculated moles</em>:
- volume = moles / molarity
- 258.808 mmol KOH / 0.440 M = 588.2 mL
Answer:
The new volume of gas would be 30 L.
Explanation:
This is an example of a Combined Gas Laws problem.