a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm
1 answer:
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Answer:
331.28 K
Explanation:
To solve this problem, you need to know that the heat that the water at 373 K is equal to the heat that the water at 285 K gains.
First, we will asume that at the end of this process there won't be any water left in gaseous state.
The heat that the steam (H20(g)) loses is equal to the heat lost because the change of phase plus the heat lost because of the decrease in temperature:
The specific Heat c of water at 298K is 4.18 kJ/K*kg.
The latent heat cl of water is equal to 2257 kJ/kg.
The heat that the cold water gains is equal to heat necessary to increase its temperature to its final value:
Remember that in equilibrium, the final temperature of both bodies of water will be equal.
Then:
Answer:
Explanation:
Given that
As both charges are negative so there exist force of repulsion in direction as shown in figure.
Angle at which force F12 is acting is
Force exerted on charge -2e is equal in magnitude to F12 but is in opposite direction
