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MAXImum [283]
2 years ago
8

a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm

osphere, what volume outside of the tire does the escaping air occupy? Some air remains within the tire occupying the original volume, but now the remaining air is at atmospheric press
Physics
1 answer:
enyata [817]2 years ago
5 0

Answer: Escaped volume = 0.0612m^3

Explanation:

According to Boyle's law

P1V1 = P2V2

P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)

P2 = atmospheric pressure= 14.696psi

V1 = volume of tire =0.025m^3

V2 = escaped volume + V1 ( since air still remain in the tire)

V2 = P1V1/P2

V2 = 50.696×0.025/14.696

V2 = 0.0862m^3

Escaped volume = 0.0862 - 0.025 = 0.0612m^3

You might be interested in
Two 60.o-g arrows are fired in quick succession with an initial speed of 82.0 m/s. The first arrow makes an initial angle of 24.
olganol [36]

Answer:

a) The first arrow reaches a maximum height of 56.712 meters, whereas second arrow reaches a maximum height of 342.816 meters, b) Both arrows have a total mechanical energy at their maximum height of 201.720 joules.

Explanation:

a) The first arrow is launch in a parabolic way, that is, horizontal speed remains constant and vertical speed changes due to the effects of gravity. On the other hand, the second is launched vertically, which means that velocity is totally influenced by gravity. Let choose the ground as the reference height for each arrow. Each arrow can be modelled as particles and by means of the Principle of Energy Conservation:

First arrow

U_{g,1} + K_{x,1} + K_{y,1} =  U_{g,2} + K_{x,2} + K_{y,2}

Where:

U_{g,1}, U_{g,2} - Initial and final gravitational potential energy, measured in joules.

K_{x,1}, K_{x,2} - Initial and final horizontal translational kinetic energy, measured in joules.

K_{y,1}, K_{y,2} - Initial and final vertical translational kinetic energy, measured in joules.

Now, the system is expanded and simplified:

m \cdot g \cdot (y_{2} - y_{1}) + \frac{1}{2}\cdot m \cdot (v_{y, 2}^{2} -v_{y, 1}^{2}) = 0

g \cdot (y_{2}-y_{1}) = \frac{1}{2}\cdot (v_{y,1}^{2}-v_{y,2}^{2})

y_{2}-y_{1} = \frac{1}{2}\cdot \frac{v_{y,1}^{2}-v_{y,2}^{2}}{g}

Where:

y_{1}. y_{2} - Initial and final height of the arrow, measured in meters.

v_{y,1}, v_{y,2} - Initial and final vertical speed of the arrow, measured in meters.

g - Gravitational acceleration, measured in meters per square second.

The initial vertical speed of the arrow is:

v_{y,1} = v_{1}\cdot \sin \theta

Where:

v_{1} - Magnitude of the initial velocity, measured in meters per second.

\theta - Initial angle, measured in sexagesimal degrees.

If v_{1} = 82\,\frac{m}{s} and \theta = 24^{\circ}, the initial vertical speed is:

v_{y,1} = \left(82\,\frac{m}{s} \right)\cdot \sin 24^{\circ}

v_{y,1} \approx 33.352\,\frac{m}{s}

If g = 9.807\,\frac{m}{s^{2}}, v_{y,1} \approx 33.352\,\frac{m}{s} and v_{y,2} = 0\,\frac{m}{s}, the maximum height of the first arrow is:

y_{2} - y_{1} = \frac{1}{2}\cdot \frac{\left(33.352\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{9.807\,\frac{m}{s^{2}} }

y_{2} - y_{1} = 56.712\,m

Second arrow

U_{g,1} + K_{y,1} =  U_{g,3} + K_{y,3}

Where:

U_{g,1}, U_{g,3} - Initial and final gravitational potential energy, measured in joules.

K_{y,1}, K_{y,3} - Initial and final vertical translational kinetic energy, measured in joules.

m \cdot g \cdot (y_{3} - y_{1}) + \frac{1}{2}\cdot m \cdot (v_{y, 3}^{2} -v_{y, 1}^{2}) = 0

g \cdot (y_{3}-y_{1}) = \frac{1}{2}\cdot (v_{y,1}^{2}-v_{y,3}^{2})

y_{3}-y_{1} = \frac{1}{2}\cdot \frac{v_{y,1}^{2}-v_{y,3}^{2}}{g}

If g = 9.807\,\frac{m}{s^{2}}, v_{y,1} = 82\,\frac{m}{s} and v_{y,3} = 0\,\frac{m}{s}, the maximum height of the first arrow is:

y_{3} - y_{1} = \frac{1}{2}\cdot \frac{\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{9.807\,\frac{m}{s^{2}} }

y_{3} - y_{1} = 342.816\,m

The first arrow reaches a maximum height of 56.712 meters, whereas second arrow reaches a maximum height of 342.816 meters.

b) The total energy of each system is determined hereafter:

First arrow

The total mechanical energy at maximum height is equal to the sum of the potential gravitational energy and horizontal translational kinetic energy. That is to say:

E = U + K_{x}

The expression is now expanded:

E = m\cdot g \cdot y_{max} + \frac{1}{2}\cdot m \cdot v_{x}^{2}

Where v_{x} is the horizontal speed of the arrow, measured in meters per second.

v_{x} = v_{1}\cdot \cos \theta

If v_{1} = 82\,\frac{m}{s} and \theta = 24^{\circ}, the horizontal speed is:

v_{x} = \left(82\,\frac{m}{s} \right)\cdot \cos 24^{\circ}

v_{x} \approx 74.911\,\frac{m}{s}

If m = 0.06\,kg, g = 9.807\,\frac{m}{s^{2}}, y_{max} = 56.712\,m and v_{x} \approx 74.911\,\frac{m}{s}, the total mechanical energy is:

E = (0.06\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (56.712\,m)+\frac{1}{2}\cdot (0.06\,kg)\cdot \left(74.911\,\frac{m}{s} \right)^{2}

E = 201.720\,J

Second arrow:

The total mechanical energy is equal to the potential gravitational energy. That is:

E = m\cdot g \cdot y_{max}

m = 0.06\,kg, g = 9.807\,\frac{m}{s^{2}} and y_{max} = 342.816\,m

E = (0.06\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (342.816\,m)

E = 201.720\,J

Both arrows have a total mechanical energy at their maximum height of 201.720 joules.

7 0
3 years ago
WHICH SIGNAL IS TRANSFERRED IN ELECTRICAL WIRE ?
Dvinal [7]

Answer:

electrical signal is transferred in electrical wire

Explanation:

electrical signals are transmitted between segments of the axon by successive opening of channels down the atonal membrane with negative and positive charge fluxing on either side of the membrane through selectively permeable chlorine , sodium or potassium channels.

hope this ans may help you.

thankyou

Mrk me brainilist

8 0
2 years ago
A stone is tossed horizontally from the highest point of a 95 m building and lands 105 m from the base of the building. Ignore a
aalyn [17]

Answer:

A) t = 4.40 s , B)   v = 23.86 m / s ,  c)  v_y = - 43.12 m / s , D)  v = 49.28 m/s

Explanation:

This is a projectile throwing exercise,

A) To know the time of the stone in the air, let's find the time it takes to reach the floor

          y = y₀ + v_{oy} t - ½ g t²

as the stone is thrown horizontally  v_{oy} = 0

          y = y₀ - ½ g t²

          0 = y₀ - ½ g t²

          t = √ (2 y₀ / g)

          t = √ (2 95 / 9.8)

          t = 4.40 s

B) what is the horizontal velocity of the body

          v = x / t

          v = 105 / 4.40

          v = 23.86 m / s

C) The vertical speed when it touches the ground

          v_y = v_{oy} - g t

          v_y = 0 - 9.8 4.40

          v_y = - 43.12 m / s

the negative sign indicates that the speed is down

D) total velocity just hitting the ground

          v = vₓ i ^ + v_y j ^

          v = 23.86 i ^ - 43.12 j ^

Let's use Pythagoras' theorem to find the modulus

          v = √ (vₓ² + v_y²)

          v = √ (23.86² + 43.12²)

           v = 49.28 m / s

we use trigonometry for the angle

          tan θ = v_y / vₓ

          θ = tan⁻¹ (-43.12 / 23.86)

            θ = -61

7 0
3 years ago
When energy is added to a fl uid, the temperature of the fl uid increases. an equation describing this phenomenon is:_________
Ksju [112]

The temperature of a fluid rises when energy is given to it. This phenomenon can be described by the equation:

Q = MCp ΔT

where,

Q is the quantity of added energy.

M is the fluid's mass.

The fluid's heat capacity is denoted by Cp.

T stands for temperature change.

<h3>What happens to a fluid's kinetic energy as the temperature rises?</h3>

The mean kinetic energy of the particles in a liquid rises with temperature. The molecules' higher average kinetic energies allow them to more easily overcome the attraction forces that keep them bound together.

<h3>Which temperature rise makes liquids more fluid?</h3>

The most significant determining factor for fluidity is pouring temperature. Therefore, the fluidity increases as the pouring temperature increases.

<h3>How does a liquid react when the temperature rises?</h3>

Particles in a solid, liquid, or gas move more quickly as its temperature rises. The particles slow down as the temperature drops. When a liquid is sufficiently cooled, it turns into a solid.

learn more about temperature of the fluid  here

brainly.com/question/4215851

#SPJ4

6 0
1 year ago
The theory of plate tectonics explains many geological events, including
OLga [1]

Answer:

D

Explanation:

The crust of the Earth is broken into many pieces called plates. The plates "float" on the soft, plastic mantle which is located below the crust, aka asthenosphere

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