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bearhunter [10]
3 years ago
6

Julio filled his gas tank with 6 gallons of premium unleaded gas for $16.98.

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer: it cost $50.94 to fill an 18 gallon tank.

Step-by-step explanation:

Julio filled his gas tank with 6 gallons of premium unleaded gas for $16.98. This means that amount it cost to will fill his gas tank with 1 gallon of premium unleaded gas would be

16.98/6 = $2.83 per gallon

Therefore, the amount of will cost to an 18 gallon tank with premium unleaded gas would be

18 × 2.83 = $50.94

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Answer:

Step-by-step explanation:

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(l*L *h)/3 =

(4*11* 9)/3 => 132 km³

4 0
2 years ago
The rubbing alcohol in hand sanitizer has a half-life of 5 seconds. If there are 36 ounces initially,
vredina [299]

Answer:

about 30 seconds

Step-by-step explanation:

Alcohol sanitizer is good until the alcohol evaporates, about 30 seconds. It is a cleaner, that kills the pathogens already on your hands. If you recontaminate your hands, you need to reapply.

4 0
3 years ago
Timothy read 3,876 pages this school year. Amelia read 3,768 pages. Who read more pages this school year? E​
12345 [234]

Answer:

Timothy

Step-by-step explanation:

Timothy because he read 3,876 pages this year.

8 0
3 years ago
Una lancha que viaja a 10 m/s pasa por debajo de un puente 3 segundos después que ha pasado un bote que viaja a 7 m/s, ¿después
ExtremeBDS [4]

Answer:

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

Step-by-step explanation:

Sea el punto debajo del puente el punto de referencia y que ambas lanchas se desplazan a velocidad a continuación, las ecuaciones cinemáticas para cada embarcación son presentadas a continuación:

Bote a 7 metros por segundo

x_{A} = x_{o}+v_{A}\cdot t (Ec. 1)

Lancha a 10 metros por segundo

x_{B} = x_{o}+v_{B}\cdot (t-3\,s) (Ec. 2)

Donde:

x_{o} - Posición debajo del puente, medido en metros.

x_{A}, x_{B} - Posición final de cada embarcación, medido en metros.

v_{A}, v_{B} - Velocidad de cada embarcación, medida en metros por segundo.

t - Tiempo, medido en segundos.

Para determinar la posición en la que ambas embarcaciones se encuentran, se debe determinar el instante en que ocurre a partir de la siguiente condición: x_{A} = x_{B}

Igualando (Ec. 1) y (Ec. 2) se tiene que:

v_{A}\cdot t = v_{B}\cdot (t-3\,s)

Ahora despejamos el tiempo:

3\cdot v_{B} = (v_{B}-v_{A})\cdot t

t = \frac{3\cdot v_{B}}{v_{B}-v_{A}}

Si sabemos que v_{B} = 10\,\frac{m}{s} y v_{A} = 7\,\frac{m}{s}, entonces:

t = \frac{3\cdot \left(10\,\frac{m}{s} \right)}{10\,\frac{m}{s}-7\,\frac{m}{s}}

t = 10\,s

Ahora, la posición de encuentro es: (x_{o} = 0\,m, v_{A} = 7\,\frac{m}{s} y t = 10\,s)

x_{A} = 0\,m + \left(7\,\frac{m}{s} \right)\cdot (10\,s)

x_{A} = 70\,m

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

6 0
3 years ago
A jar of jam contains 55% fruit.How much fruit would I need for ten 454g jars of jam?​
Svetach [21]
10x454x0.55=2,497 grams of fruit
5 0
3 years ago
Read 2 more answers
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