2 years ago

The velocity of an ocean wave is 5m/s. The distance between crests is 3m. What is the frequency of the wave

Physics

1 answer:

alexgriva [62]2 years ago

4 0

Answer:

1.67m

5m/s

Explanation:

Wavelength of the wave = 3m

Speed of the wave = 5m/s

The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.

To find the frequency ;

V = f∧

V is the speed of the wave

f is the frequency

∧ is the wavelength

Insert the parameters and find the frequency;

f = V/ ∧ = 5 / 3 = 1.67Hz

The rate at which the wave passed a given point is the speed of the wave and it is 5m/s

You might be interested in

John runs around a 126.5 m circular track 3.5 times in 4.17 minutes. What is his average speed?

sdas [7]

Average speed = distance traveled / time

average speed = (126.5 m * 3.5 laps) / (4.17 min)

= 106.2 m/min

6 0

2 years ago

a pelican flying along a horizontal path drops a fish from a height of 5.4m. the fish travels 8.0m horizontally before it hits t

oksian1 [2.3K]

Answer:

7.0 m/s

Explanation:

6 0

2 years ago

The Orion nebula is one of the brightest diffuse nebulae in the sky (look for it in the winter, just below the three bright star

Oxana [17]

Answer:

T=183.21K

Explanation:

We have to take into account that the system is a ideal gas. Hence, we have the expression

$PV=nRT$

where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant.

Thus, it is necessary to calculate n and V

V is the volume of a sphere

$V=\frac{4}{3}\pi r^3=\frac{4}{3}\pi (5.9*10^{15}m)^3=8.602*10^{47}m^3$

V=8.86*10^{50}L

and for n

$n=\frac{(4000M_s)/(2*mH)}{6.022*10^{23}mol^{-1}}=3.95*10^{36}mol$

Hence, we have (1 Pa = 9.85*10^{-9}atm)

$T=\frac{PV}{nR}=\frac{(6.8*10^{-9}*9.85*10^{-6}atm)(8.86*10^{50}L)}{(0.0820\frac{atm*L}{mol*K})(3.95*10^{36}mol)}\\\\T=183.21K$

hope this helps!!

8 0

2 years ago

Help please!!!!!!!!!!!!

Elena-2011 [213]

A would be most useful (Carbon dating)

3 0

2 years ago

A square sheet of rubber has sides that are 20 cm long. If you stretch it so that the area of the rubber is four times larger, h

oee [108]

Answer:

400

Explanation:

Trust me its correct

7 0

2 years ago

Read 2 more answers