Volume of gold in the phone = 10 cm^3
= 0.<span>00001 m^3 </span>
Density of gold = 19300 kg/m^3
1 kg mass = 2.2 pounds
Mass of 10 cm^3 of gold = 0<span>.00001 m^3 * (19300 kg/m^3)
= 0.193 kg
So
0.193 kg = 0.193 * 2.2 pounds
= 0.43 pounds
I think there is something wrong with the options given in the question.</span>
What it looks to be that you found in A was the "initial"...b/c the question asks:
<span>"how much energy does the electron have 'initially' in the n=4 excited state?" </span>
<span>"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. </span>
The answer comes to: <span>−1.36×10^−19 J</span>
You use the same equation for the second part as for part a.
<span>just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer. </span>
Areas of rising air causes low air pressure areas and <span>Areas of sinking air are areas of high air </span>pressure
Answer: Average Velocity = - 643.42 i + 512.66 j m/s
Magnitude = 822.7 m/s
Direction = 141.45°
Explanation:
r = 3.84 x 10^8 m
w = 2.46 x 10^-6 rad/s
Formula for Average velocity = displacement / time
at t = 0
x(0) = r
y(0) = 0
at t = 8.45 days
= 8.45 x 24 x 3600 s =730080 sec
w t = 2.46 x 10^-6 x 730080 = 1.80 rad Or 102.90°
xf = r cos(w t) = - 0.2233r
yf = r sin(w t) = 0.9747r
Displacement = (xf - x0)i + (yf - y0)j = -1.2233r i + 0.9747r j
<v> = dispalcement / t = (-1.2233r i + 0.9747r j ) / (730080 s )
= - 643.42 i + 512.66 j m/s
Magnitude
= sqrt(643.42^2 + 512.66^2)
= 822.7 m/s
Direction
= 180 - tan^-1(512.66 / 643.42)
= 141.45°
