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3 years ago

What can fall but never get hurt

Physics

2 answers:

Vladimir [108]3 years ago

4 0

It’s either snow or rain if it’s a riddle sort of.

aliya0001 [1]3 years ago

4 0

ant

ant can fall but never get hurt because of the weight it is having

and the air medium reduce the speed at which it falls

there for ant falls and never get hurt

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How much will be the net displacement if a car travels 6 km east and then travels 14 km west

ExtremeBDS [4]

8km is the displacement

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3 years ago

In which stage of a star's life cycle, does gravity and fusion become balanced, and an adult star forms?

V125BC [204]

Answer:

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3 years ago

Find the pressure exerted on the floor by a 100N box whose bottom area is 40cm x 50cm.

Mazyrski [523]

Answer:

Pressure exerted = 500 Pa

Explanation:

The formula for pressure is as follows:

$Pressure = \frac{Force \space\ applied}{Area}$

In this case,

Force applied = 100N

Area = 40cm × 50cm = 2000cm² = 2000 × 10⁻⁴ = 0.2m²

Substituting these values into the formula:

Pressure = $\frac{100}{0.2}$

⇒ Pressure = 500 Pa

3 0

2 years ago

Read 2 more answers

A single-turn current loop, carrying a current of 4.03 A, is in the shape of a right triangle with sides 68.1, 151, and 166 cm.

SashulF [63]

Answer:

Part a)

$F = 0$

Part b)

$F = 0.25 N$

Part c)

$F = 0.25 N$

Part d)

Net force on a closed loop in uniform magnetic field is always ZERO

$F_{net} = 0$

Explanation:

As we know that force on a current carrying wire is given as

$\vec F = i(\vec L \times \vec B)$

now we have

Part a)

current in side 166 cm and magnetic field is parallel

so we have

$F = i(\vec L \times \vec B)$

here we know that L and B is parallel to each other so

$F = 0$

Part b)

For 68.1 cm length wire we have

$F = iLB sin\theta$

here we know that

$cos\theta = \frac{68.1}{166}$

$\theta = 65.8$

so we have

$F = (4.03)(0.681)(99.3 \times 10^{-3})sin65.8$

$F = 0.25 N$

Part c)

For 151 cm length wire we have

$F = iLB sin\phi$

here we know that

$cos\phi = \frac{151}{166}$

$\theta = 24.5$

so we have

$F = (4.03)(1.51)(99.3 \times 10^{-3})sin24.5$

$F = 0.25 N$

Part d)

Net force on a closed loop in uniform magnetic field is always ZERO

$F_{net} = 0$

4 0

2 years ago

Equipotential surfaces a) make an angle of 45 degrees with the electric field. b) are parallel to the electric field. c) are per

Schach [20]

Answer:

Option c) are perpendicular to the electric field

Explanation:

Equipotential surfaces are perpendicular to the electric field. the electric field lines are projected outwards from the equipotential surface, i.e., the lines of the electric field are at 90 $^{\circ}$ to the equipotential surface.

Equipotential surface are those surfaces that have the same potential at any point on the surface. Thus the potential difference at any point on the surface is zero due to same potential.

Any charge particle on this surface will move in a perpendicular direction to the Coulombian force. No work is done by the force on a particle moving on an equipotential surface.

7 0

3 years ago