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3 years ago

Sometimes human actions can have both positive and negative environmental impacts.

1 answer:

3 0

Besides the negative environmental impact of dams there are also many positive environmental impact of dams. Dams help to prevent flooding and the water can be stored to provide energy like the hydro electric power

Explanation:

When a dam is constructed in a area whenever there is drought in the areas the stored water in the dam will be helpful for irrigation and drinking purpose. The water stored are made to fall on the turbines and produce hydro electric power

Dams even help to prevent floods excess of water will be stored in the dam and hence the effect of flooding will be reduced and the water stored can be used efficiently

These are some of the positive environmental impacts of the dam

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Consider the following reaction at equilibrium. What will happen if SO2SO2 is added to the reaction? 4FeS2FeS2(s) + 11O2O2(g) ⇌⇌

kupik [55]

Answer:

The equilibrium will change in the direction of the reactants

Explanation:

7 0

3 years ago

What is the general name for the poisonous compounds found in toxic frogs

Ivahew [28]

I think it is dendrobatidae that is poisonous in frogs. Hope this helps!

6 0

3 years ago

Methane, a component in natural gas, can be used as a fuel in combustion reactions. What is the value for ΔGnon (in kJ) for the

Oksanka [162]

Answer: The $\Delta G$ for the reaction is -806.86 kJ

Explanation:

We are given:

$\Delta H^o_{rxn}=-803kJ=-803000J$ (Conversion factor: 1 kJ = 1000)

$\Delta S^o_{rxn}=-4.05J/K$

Temperature of the reaction = 293 K

To calculate the standard Gibbs's free energy of the reaction, we use the equation:

$\Delta G^o_{rxn}=\Delat H^o_{rxn}-T\Delta S^o_{rxn}$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=-803000J-[(293K)\times (-4.05J/K)]=-801813.35J$

For the given chemical equation:

$CH_4(g)+2O_2(g)\rightleftharpoons CO_2(g)+2H_2O(g)$

The expression for $K_c$ is given as:

$K_{c}=\frac{[H_2O]^2[CO_2]}{[CH_4][O_2]^2}$

We are given:

$[H_2O]=6.41M$

$[CO_2]=3.83M$

$[CH_4]=14.51M$

$[O_2]=9.27M$

Putting values in above equation, we get:

$K_c=\frac{(6.41)^2\times 3.83}{14.51\times (9.27)^2}$

$K_c=0.126$

To calculate the Gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_c$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = -801813.35 J

R = Gas constant = $8.314J/K mol$

T = Temperature = 293 K

$K_c$ = equilibrium constant in terms of concentration = 0.126

Putting values in above equation, we get:

$\Delta G=-801813.35J+(8.314J/K.mol\times 293K\times \ln(0.126))$

$\Delta G=-806859.46J=-806.86kJ$

Hence, the $\Delta G$ for the reaction is -806.86 kJ

8 0

3 years ago

2Fe2O3+3C_4Fe+3 CO2 how many moles of Carbon are needed to produce 1.9 moles of iron (Fe)?

Bad White [126]

Um use English no offense

7 0

3 years ago

The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-

lara31 [8.8K]

Answer:

the total gas pressure after one half-life is 4.38 atm

Explanation:

The balanced equation for the decomposition of N2O to N2 and O2 is given as:

2N₂O(gas) ⇒ 2N₂(gas) + O₂(gas)

2 moles of N₂O produce 2 moles of N₂ and 1 mole of O₂

The change in pressure depends on the coefficient (number of moles) of the reactant and product.

N₂O N₂ O₂

number of moles 2 2 1

Initial pressure (atm) 3.50 0 0

change in pressure -2x +2x x

Final pressure (atm) 3.50 - 2x 2x x

The total final pressure is the sum of the individual total pressure. i.e.:

Total final pressure = final pressure of N₂O + final pressure of N₂ + final pressure of O₂

Total final pressure = (3.5 - 2x) + (2x) + x

Total final pressure = 3.5 + x

After one half life, the initial pressure of N₂O would be half its value.

Final pressure of N₂O = half of the initial pressure of N₂O

3.5 - 2x = 0.5(3.5)

3.5 - 2x = 1.75

2x = 1.75

x = 0.875 atm

Therefore, Total final pressure = 3.5 + x = 3.5 + 0.875

Total final pressure = 4.38 atm to 3 significant figures

4 0

3 years ago