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spayn [35]
3 years ago
5

2Fe2O3+3C_4Fe+3 CO2 how many moles of Carbon are needed to produce 1.9 moles of iron (Fe)?​

Chemistry
1 answer:
Bad White [126]3 years ago
7 0
Um use English no offense
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likoan [24]

Answer:

BBB

Explanation:

8 0
3 years ago
Read 2 more answers
Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2
erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0
3 years ago
An inverse relationship can be represented by what?
Umnica [9.8K]

Answer:

1/....

Explanation:

If we say acceleration 'a' is inversely proportional to mass 'm', then

a=1/m.

8 0
2 years ago
Imagine that you run this experiment and that the initial change in pressure is 0.0023 atm/s. what is the initial reaction rate?
svet-max [94.6K]

\text{reaction rate} = 9.6 \times 10^{-5} \; \text{mol}\cdot\text{L}^{-1} \cdot \text{s}^{-1}

Explanation:

Concentration c = n / V;

The reaction see a 0.0023 \; \text{atm} change in pressure per second. By the ideal gas law, this quantity would correspond to a change in concentration, n/V of

c = n / V = P / (n \cdot R) = 0.0023 / ((273.15 + 20) \times 0.0821 ) = 9.6 \times 10^{-5} \; \text{mol}

where the ideal gas constant R = 0.0821 \; \text{L} \cdot \text{atm} \cdot \text{mol}^{-1} \cdot \text{K}^{-1}.

By definition, \text{reaction rate} = \Delta \text{concentration} / \Delta\text{time}

Therefore, for this particular reaction

\text{rate} = 9.6 \times 10^{-5} \; \text{mol} / (1 \; \text{s} ) = 9.6 \times 10^{-5} \; \text{mol}  \cdot \text{L}^{-1} \cdot \text{s}^{-1}

6 0
3 years ago
How many grams of glucose(C6H12O6) are produced by 10.0 grams of water(H2O)?
GaryK [48]

Answer:

16.7 g of glucose

Explanation:

Convert grams of H₂O to moles.  <em>0.555 mol</em>

We can use the chemical equation to determine the theoretical yield.  Based on the equation, for every 6 moles of H₂O, 1 mole of glucose is produced.  The ratio of glucose moles to H₂O moles is 1/6.  

Multiply the moles of H₂O by the ratio to find moles of glucose.  <em>0.0925 mol</em>

Convert moles of glucose to grams.  <em>16.7 g</em>

3 0
3 years ago
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