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DiKsa [7]
3 years ago
7

HELLPPPP ASAPPPPP

Chemistry
2 answers:
Nataliya [291]3 years ago
6 0
If you increase recycling, there will be less garbage for the landfills I guess.
Pavel [41]3 years ago
5 0
The answer would be a Decrease in landfill usage
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What causes the colors observed during a flame test
Marrrta [24]

By using flame test we can identify the elements because colors which are given by elements with flame test are unique.

During the flame test, the electrons of the atom which are in ground state absorb energy and go to upper level. This is called electron excitation. Excited electrons are unstable. Hence, they come back to the ground state by emitting the energy as photons. If that released energy has a frequency which belongs to visual light, then that wave gives a color.

3 0
3 years ago
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Which of the following landforms (physical features) was formed when two landmasses collided?
IrinaK [193]
Mariana Trench and the Himalayan Mountains
8 0
3 years ago
KF is a strong electrolyte, & HF is a weak electrolyte. How are they different?
Vitek1552 [10]

The strong electrolyte KF completely dissociates into K+ and F- ions when it dissolves in water. When the weak electrolyte HF dissolves in water, there are a few ions of H+ and F- present, but mostly dissolved HF molecules. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

7 0
3 years ago
An example of an atom that has no charge is one that has
VikaD [51]
<span>For an atom to have no charge, that is neutral, the number of electrons should be the same to the number of electrons. If the number of electron is more than the number of proton, the atom is negatively charged. Also, when the number of proton is more than the number of electron, the atom is positively charged. The answer to this item is letter C. </span>
7 0
3 years ago
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The energy of a gamma ray photon whose frequency is 5.02 x 1020 Hz?
vichka [17]

Answer:

The energy of photon is 33.28×10⁻¹⁴  J

Explanation:

Given data:

Frequency of photon = 5.02×10²⁰ Hz

Energy of photon = ?

Solution:

E = h.f

h = planc'ks constant = 6.63×10⁻³⁴ Js

by putting values,

E =  6.63×10⁻³⁴ Js × 5.02×10²⁰ Hz

        Hz = s⁻¹

E = 33.28×10⁻¹⁴  J

The energy of photon is 33.28×10⁻¹⁴  J.

4 0
3 years ago
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