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Masja [62]
3 years ago
7

Calculate the following question​

Chemistry
1 answer:
valkas [14]3 years ago
6 0

Answer:

[H₃O⁺] → 0.063 M

Explanation:

To determine the pH, our formula is:

- log [H₃O⁺]

To determine the [H⁺] we have to apply the inverse function

10^-pH = [H₃O⁺]

10⁻¹'²⁰ = [H₃O⁺] → 0.063 M

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Answer:

b

Explanation:

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Which of the following is a change in physical composition?it could be D. A brick being ground up into fine dust. as this is a change from one physical form to another                                                                                                                             Which of the following is a change in chemical composition?  would be A. A white precipitate forming as a result of the combination of two liquids. as this is a clear chemical change                                                                                What kind of bond would you expect between H, S and O?  i belive it would be D. Covalent                                                                                      

Which of the following is not one of the three processes of the hydrologic cycle?  this gose to B. Collection the water cycle has nothing to do with this so there for its not part of the cycle

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3 years ago
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4 years ago
The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10
Sati [7]

Answer:

a. 113 min

Explanation:

Considering the equilibrium:-

                   2N₂O₅ ⇔ 4NO₂ + O₂

At t = 0        125 kPa

At t = teq     125 - 2x      4x        x

Thus, total pressure = 125 - 2x + 4x + x = 125 - 3x

125 - 3x = 176 kPa

x = 17 kPa

Remaining pressure of N₂O₅ = 125 - 2*17 kPa = 91 kPa

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 2.8\times 10^{-3} min⁻¹

Initial concentration [A_0] = 125 kPa

Final concentration [A_t] = 91 kPa

Time = ?

Applying in the above equation, we get that:-

91=125e^{-2.8\times 10^{-3}\times t}

125e^{-2.8\times \:10^{-3}t}=91

-2.8\times \:10^{-3}t=\ln \left(\frac{91}{125}\right)

t=113\ min

3 0
3 years ago
At which temperature do the molecules of an ideal gas have 3 times the kinetic energy they have at 32of?
algol [13]

Answer:

  • 820 K

Explanation:

As per Boltzman equation, <em>kinetic energy (KE)</em> is in direct relation to the <em>temperature</em>, measured in absolute scale Kelvin.

  • KE α T.

Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>

So, you must just convert the given temperature, 32°F, to kelvin scale.

You can do that in two stages.

  • First, convert 32°F to °C. Since, 32°F is the freezing temperature of water, you may remember that is 0°C. You can also use the conversion formula: T (°C) = [T (°F) - 32] / 1.80

  • Second, convert 0°C to kelvin:

         T (K) = T(°C) + 273.15 K= 273.15 K

Then, <u>3 times</u> gives you: 3 × 273.15 K = 819.45 K

Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.

7 0
3 years ago
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