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4 years ago

67+k = 83 solve for k no work needed

Mathematics

1 answer:

kumpel [21]4 years ago

3 0

Answer:

k = 16

Step-by-step explanation:

Isolate the variable, k. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operation, and =

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

Subtract 67 from both sides of the equation:

k + 67 = 83

k + 67 (-67) = 83 (-67)

k = 83 - 67

k = 16

16 is your answer for k.

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Answer:

b. Kinsey must save $72 per month to achieve her goal.

Step-by-step explanation:

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4 years ago

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Solve by taking the square root I need help understanding steps this is hard for me.

Shalnov [3]

Answer:

x= $-2 \pm \sqrt{13}$

Step-by-step explanation:

Given: $3x^{2} -12x+27= 0$

This is a quadratic equation.

$3x^{2} -12x+27= 0$

Taking common 3 from the equation given

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dividing both side by 3

⇒ $x^{2} -4x+9=0$

By using different factor, we can observe this trinomial can not be factored.

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⇒ $x^{2} -4x+4= 13$

we know, $(x+2)^{2} = x^{2} +2\times x\times 2+2^{2}$

∴ $(x+2)^{2} =13$

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3 years ago

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3 years ago

It is known that 45% of senior citizens are deficient in vitamin D. Let Y be the number of vitamin D efficient individuals in a

Mashutka [201]

Answer:

a ) 0.1403604645 and 0.1368

b) 0.3464961 and 0.3485

c) 0.802671982 and 0.8018

Step-by-step explanation:

Y~ B (15,0.45)

Y~ N (15*0.45, 15*0.45*0.55) = Y~ N (6.75, 3.7125)

a) P(Y=5) = 15C5 (0.45)^5 * (0.55)^10 = 0.1403604645

For normal approximation

P(Y = 5 ) = P ( 4.5 < Y < 5.5 ) ......... continuity correction

Hence,

$P ( 4.5 < Y < 5.5 ) = P ( \frac{4.5 - 6.75}{\sqrt{3.7125} } < Z < \frac{5.5 - 6.75}{\sqrt{3.7125} } ) = P ( -1.16775 < Z < -0.64875 )$

The probability P ( 4.5 < Y < 5.5 ) = 0.1368

b) P(Y>7) = 15C8 (0.45)^ 8 (0.55)^7 + 15C9 (0.45)^9 * (0.55)^6 + 15C10 (0.45)^10 * (0.55)^5 + 15C11 (0.45)^11 * (0.55)^4 + 15C12 (0.45)^12 * (0.55)^3 + 15C13 (0.45)^13 * (0.55)^2 + 15C14 (0.45)^14 * (0.55) + (0.45)^15

= 0.3464961

For normal approximation

P(Y > 7 ) = P (Y > 7.5 ) ......... continuity correction

Hence,

$P (Y > 7.5) = P (Z > \frac{7.5-6.75}{\sqrt{3.7125} } ) = P (Z > 0.389249)\\$

The probability P ( Y>7.5 ) = 0.3485

c) P (4 < Y < 10) = 15C5 (0.45)^5 (0.55)^10 + 15C6 (0.45)^ 6 (0.55)^9 + 15C7 (0.45)^7 (0.55)^8 + 15C8 (0.45)^ 8 (0.55)^7 + 15C9 (0.45)^9 * (0.55)^6

= 0.802671982

For normal approximation

P( 4 < Y < 10 ) = P (4.5< Y < 9.5 ) ......... continuity correction

Hence,

$P ( 4.5 < Y < 9.5 ) = P ( \frac{4.5 - 6.75}{\sqrt{3.7125} } < Z < \frac{9.5 - 6.75}{\sqrt{3.7125} } ) = P ( -1.167748416 < Z < 1.427248064 )$

The probability P (4.5< Y < 9.5 ) = 0.8018

8 0

3 years ago