First you need to make a difference between friction while object is stationary and the friction while object is moving. Force required to start moving some object is slightly greater than force required to maintain objects movement. That means that to move a chair you need some force F1 but you can than slightly reduce force and chair will still be moving.
Now to the problem in this question: It can be said that "stationary friction force" is equal to 15 Newtons. Its also good to know that friction force between chair and floor while you are increasing your push is also increasing and is equal to force of your push. Once it reaches 15N which is it "critical value" for that chair, chair starts moving and friction force drops a little bit and now it is called friction force of moving chair.
The following
are the answers to the questions presented:
a. The joules of energy required to run a 100W light bulb for one day is 8640000J
b. The amount of coals that has to be burned to light that light bulb for one day is 0.96kg
The solution would
be like this for this specific problem:
<span>P=<span>W/s</span>→W=Pt=100W1day <span><span>24h/</span><span>1day </span></span><span><span>3600s/</span><span>1h</span></span>=8640000J</span>
<span>W=<span>30/100</span>wm→m=<span><span>100W/</span><span>30w</span></span>=<span><span>100×8640000J/</span><span>30×30×<span>10in thepowerof6 </span><span>J/<span>kg</span></span></span></span>=0.96kg</span>
<span>I am hoping that
these answers have satisfied your queries and it will be able to help you in
your endeavors, and if you would like, feel free to ask another question.</span>
Answer:
The magnitude of F₁ is 3.7 times of F₂
Explanation:
Given that,
Time = 10 sec
Speed = 3.0 km/h
Speed of second tugboat = 11 km/h
We need to calculate the speed
The force F₁is constant acceleration is also a constant.
We need to calculate the acceleration
Using formula of acceleration
Similarly,
For total force,
The speed of second tugboat is
We need to calculate total acceleration
We need to calculate the acceleration a₂
We need to calculate the factor of F₁ and F₂
Dividing force F₁ by F₂
Hence, The magnitude of F₁ is 3.7 times of F₂
