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Marizza181 [45]
3 years ago
6

zybooks One AA battery in a flashlight stores 9400 J. The three LED flashlight bulbs consume 0.5 W. How many hours will the flas

hlight last?
Physics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

The time for which the flashlight last is 5.23 hours.

Explanation:

Given that,

One AA battery in a flashlight stores 9400 J, E = 9400 J

Power consumed by the LED flashlight bulbs, P = 0.5 W

We need to find the time for which the flashlight last. The power of a device is given by the energy stored per unit time as :

P=\dfrac{E}{t}

t=\dfrac{E}{P}

t=\dfrac{9400\ J}{0.5\ W}

t = 18800  seconds

or

Since, 1 hour = 3600 seconds

t = 5.23 hours

So, the time for which the flashlight last is 5.23 hours. Hence, this is the required solution.

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Firdavs [7]

Initial velocity (u) = 2 m/s

Acceleration (a) = 10 m/s^2

Time taken (t) = 4 s

Let the final velocity be v.

By using the equation,

v = u + at, we get

or, v = 2 + 10 × 4

or, v = 2 + 40

or, v = 42

The final velocity is 42 m/s.

5 0
2 years ago
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6. If two objects experience the same net force, but they have different masses, which object will accelerate at
Digiron [165]

Answer:

i would say the heavier object

4 0
3 years ago
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A boy is pulling a load of 150N with a string inclined at an angle 30 to the horizontal if the tension of string is 105N the for
Lorico [155]

The force tending to lift the load (vertical force) is equal to <u>22.5N.</u>

Why?

Since the boy is pulling a load (150N) with a string inclined at an angle of 30° to the horizontal, the total force will have two components (horizontal and vertical component), but we need to consider the given information about the tension of the string which is equal to 105N.

We can calculate the vertical force using the following formula:

VerticalForce=Force*Sin(30\° )=(BoysForce-StringForce)*\frac{1}{2}\\\\VerticalForce=(150N-105N)*\frac{1}{2}=VerticalForce=45N*\frac{1}{2}=22.5N

Hence, we can see that <u>the force tending to lift the load</u> off the ground (vertical force) is equal to <u>22.5N.</u>

Have a nice day!

8 0
3 years ago
A penny has a mass of 2.50 g, a diameter of 19.55 mm, and a thickness of 1.55 mm. Calculate the density of the material from whi
Dmitry [639]
Density = (mass) divided by (volume)

We know the mass (2.5 g).  We need to find the volume.

The penny is a very short cylinder.
The volume of a cylinder is (π · radius² · height).
The penny's radius is 1/2 of its diameter = 9.775 mm.
The 'height' of the cylinder is the penny's thickness = 1.55 mm.

Volume  =  (π) (9.775 mm)² (1.55 mm)

             =  (π) (95.55 mm²) (1.55 mm)

             =  (π) (148.1 mm³)

             =        465.3 mm³

We know the volume now.  So we could state the density of the penny,
but nobody will understand what we have.  Here it is:

         mass/volume = 2.5 g / 465.3 mm³  =  0.0054 g/mm³  .

Nobody every talks about density in units of ' gram/(millimeter)³ ' .
It's always ' gram / (centimeter)³ '.
So we have to convert our number for the volume.

                         (0.0054  g/mm³)  x  (10 mm / cm)³

                 =      (0.0054 x 1,000)  g/cm³

                 =          5.37  g/cm³  .

This isn't actually very close to what the US mint says for the density
of a penny, but it's in a much better ball park than 0.0054 was.
4 0
3 years ago
What property is an acid-base indicator used to measure?
Volgvan

Answer:

ph

Explanation:

4 0
3 years ago
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