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Marizza181 [45]
3 years ago
6

zybooks One AA battery in a flashlight stores 9400 J. The three LED flashlight bulbs consume 0.5 W. How many hours will the flas

hlight last?
Physics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

The time for which the flashlight last is 5.23 hours.

Explanation:

Given that,

One AA battery in a flashlight stores 9400 J, E = 9400 J

Power consumed by the LED flashlight bulbs, P = 0.5 W

We need to find the time for which the flashlight last. The power of a device is given by the energy stored per unit time as :

P=\dfrac{E}{t}

t=\dfrac{E}{P}

t=\dfrac{9400\ J}{0.5\ W}

t = 18800  seconds

or

Since, 1 hour = 3600 seconds

t = 5.23 hours

So, the time for which the flashlight last is 5.23 hours. Hence, this is the required solution.

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3 years ago
What is the current in a 160V circuit if the resistance is 2Ω?<br> V=<br> I=<br> R=
Alex787 [66]

Explanation:

v = IR

v= 160 R = 2

<u>160</u> = <u>2I</u>

2 2

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4 0
2 years ago
Can someone please help me with this question? ASAP thank you!
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3 years ago
Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t
LiRa [457]

Answer:

The minimum coefficient of friction is 0.544

Solution:

As per the question:

Radius of the curve, R = 48 m

Speed of the car, v = 16 m/s

To calculate the minimum coefficient of static friction:

The centrifugal force on the box is in the outward direction and is given by:

F_{c} = \frac{mv^{2}}{R}  

f_{s} = \mu_{s}mg

where

\mu_{s} = coefficient of static friction

The net force on the box is zero, since, the box is stationary and is given by:

F_{net} = f_{s} - F_{c}  

0 = f_{s} - F_{c}  

\mu_{s}mg = \frac{mv^{2}}{R}  

\mu_{s} = \frac{v^{2}}{gR}  

\mu_{s} = \frac{16^{2}}{9.8\times 48} = 0.544  

3 0
3 years ago
A cubic tank holds 1,000.0 kg of water. what are the the dimensions of the tank in meters? explain your reasoning
Scilla [17]

Given: A cubic tank holds 1,000.0 kg of water.

Mass of water in tank (m) = 1000.0 kg

Density of water (d) = 1000.0 kg /m³

Concept: Volume(V) = Mass / Density

Since the tank holds these water in it so the volume of water will be equal to the volume of the tank.

Hence, the volume of the tank = Mass of water / Density of water

or,                                         =  1000.0 kg / 1000.0 kg m⁻³

or,                                       = 1.0 m³

Since tank is cubical in shape. Let its side be 'x'

The volume of tank (x³) = 1.0 m³

or.          side of tank (x) = 1.0 m

Hence, the dimensions of the tank will be 1.0 m.

8 0
4 years ago
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