What must be the same on each side of a chemical equation, because of the law of conservation of matter?

2 answers:

8 0

Actually, as long as you end up with as much matter as you started with, you should be fine. You cannot create matter out of nothing and you can’t have it just disappear during a chemical equation :)

Dafna1 [17]3 years ago

5 0

The amount of each element must be the same on each side.

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What are magnetic poles an indication of

Leokris [45]

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6 0

3 years ago

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Two 2.0-cm-diameter insulating spheres have a 6.60 cm space between them. One sphere is charged to + 76.0 nC , the other to - 30

e-lub [12.9K]

Answer:

$5.2\times 10^5N/C$

Explanation:

Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.

This can be easily seen if we use Gauss's law, $\int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}$

We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,

$E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}$

which is the same as that of a point charge.

In our problem the charges being of opposite signs, the electric field will add up. Therefore,

$E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C$

where, $r$ = distance between the center of one sphere to the midpoint (between the 2 spheres)

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3 years ago

Which of the following is true about a planet orbiting a star in uniform circular motion? A. The direction of the velocity vecto

Luda [366]

<span>As it is uniform circular motion therefore speed is constant. Therefore we can rule out option B. Also in circular motion the direction of velocity vector changes therefore velocity can't be constant. Therefore option B is incorrect as well. Also centripetal acceleration is always towards the center so option D is wrong as well. That implies option A is correct.</span>

4 0

4 years ago

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Xelga [282]

Answer:

$\lambda=1282\ nm$

Explanation:

$E_n=-2.179\times 10^{-18}\times \frac{1}{n^2}\ Joules$

For transitions:

$Energy\ Difference,\ \Delta E= E_f-E_i =-2.179\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$