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ra1l [238]
3 years ago
14

What must be the same on each side of a chemical equation, because of the law of conservation of matter?

Physics
2 answers:
elixir [45]3 years ago
8 0
Actually, as long as you end up with as much matter as you started with, you should be fine. You cannot create matter out of nothing and you can’t have it just disappear during a chemical equation :)
Dafna1 [17]3 years ago
5 0
The amount of each element must be the same on each side.
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A hockey ball accelerates from 0.m/s to 25m/s in 0.05 seconds what is the acceleration of the ball ?
S_A_V [24]

Answer:

500

Explanation:

25/0.05 .

I think this ?

3 0
3 years ago
A car accelerates from rest at 3.6 m/s 2 . How much time does it need to attain a speed of 5 m/s?
Olenka [21]

car starts from rest

v_i = 0

final speed attained by the car is

v_f = 5 m/s

acceleration of the car will be

a = 3.6 m/s^2

now the time to reach this final speed will be

t = \frac{v_f - v_i}{a}

t = \frac{5 - 0}{3.6}

t = 1.39 s

so it required 1.39 s to reach this final speed

6 0
3 years ago
A vector points -1.55 units along the x-axis and 3.22 units along the y-axis what is the magnitude of the vector
Rasek [7]

Answer:

3.57 units

Explanation:

x =\sqrt{ (-1.55)^2+(3.22)^2} = 3.57 units

5 0
3 years ago
Read 2 more answers
A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 36 m/s when i
Ganezh [65]

Answer:

its speed when its height was half that of its starting point is 25.46 m/s

Explanation:

Given;

final speed of the roller coaster, v = 36 m/s

Applying general equation of motion;

V² = U² + 2gh

where;

V is the final speed of the roller coaster

U is the initial speed of the roller coaster = 0

h is the height attained at a given velocity

36² = 0 + (2 x 9.8)h

1296 = 19.6 h

h = 1296/19.6

h = 66.1224 m

when its height was half that of its starting point, h₂ = ¹/₂ h

h₂ = ¹/₂(66.1224 m) = 33.061 m

At h = 33.061 m, V = ?

V² = U² + 2gh

V² = 0 + 2 x 9.8 x 33.061

V² = 648

V = √648

V = 25.46 m/s

Therefore, its speed when its height was half that of its starting point is 25.46 m/s

8 0
3 years ago
A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 3.00 s.
Misha Larkins [42]

Answer:

Explanation:

Initial velocity of mailbag u = 2 m/s

acceleration downwards a = g = 9.8 m/s²

time t = 3 s

a ) final velocity v = ?

v = u + at

= 2 + 9.8 x 3

= 31.4 m /s

b )

s = ut + 1/2 g t²

s is relative displacement of mailbag

u = relative initial velocity of mailbag = 0

relative acceleration = g = 9.8 m /s²

time t = 3 s

s = 0 + 1/2 x 9.8 x 3²

= 44.1 m

relative displacement of mailbag = 44.1 m .

4 0
2 years ago
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