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luda_lava [24]
3 years ago
15

2. A square is divided into smaller squares and

Mathematics
2 answers:
Yanka [14]3 years ago
7 0
Since the length is divided into 4 parts it would equal 0.5ft
Oduvanchick [21]3 years ago
4 0

Answer:

1.5 ft^2

Step-by-step explanation:

Since the length is divided into 4 parts,

Length of a small square = 2/4

= 0.5 ft

Hence,

Area of 1 small square = (0.5)(0.5)

= 0.25 ft^2

Area of shaded portion = Area of 6 small squares

= 6(0.25)

= <u>1.5 ft^2</u>

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Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an
marishachu [46]

Answer: x+x^2+x^3+x^4

Step-by-step explanation:

As per given,

Number of wives = x

Number of sacks = x (\text{Number of wives} )= x\times x = x^2

Number of cats = x(\text{Number of sack})= x \times x^2=x^3

Number of kits = x(\text{Number of cats} )=x\times x^3=x^4

Now , the total number of kits, cats, sacks, and wives going to St. Ives = x+x^2+x^3+x^4

Hence, the required ex[pression:  x+x^2+x^3+x^4

5 0
3 years ago
Deena has 4 pairs of of white socks , 3 pairs of black sock, 1 pair of red socks, and 2 pairs of Navy socks in her drawer each p
VikaD [51]

Answer:

2/5

Step-by-step explanation:

Ok there are 4+3+1+2 pairs of socks in all... Aka 10 sock pairs in all.

There are 4 white pairs.  So the probability she selects a white pair is 4/10.

4/10 can be reduced to 2/5.

7 0
2 years ago
Read 2 more answers
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
ILL GIVE BRAINLIEST<br><br>SHOW ALL WORK
RideAnS [48]

Answer:

9/20 mile^2

Step-by-step explanation:

9/10 x 1/2 = 9/20

3 0
3 years ago
Read 2 more answers
I'll mark u brainliest for the right answer and 15 POINTS!!!
morpeh [17]

The sum of all angles in a regular octagon is 1080 degrees. Because all sides are the same (regular octagon), all of the eight angles are the same too, so we simply divide 1080 by 8 and that is the solution.

1080/8 = 135

8 0
3 years ago
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