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nignag [31]
3 years ago
7

The gold-like mineral in the metamorphic rock pictured below is known as pyrite. When pyrite is exposed to air and water it can

react
to form sulfate and an acid. The acid can discolor and eat away the surrounding rock.
Image courtesy of David Usher, USGS
Pyrite breaks down rocks in which of the following processes?
A
deposition
B. physical weathering
C.
erosion
D.
chemical weathering
Physics
2 answers:
Pepsi [2]3 years ago
4 0

Answer:

Chemical Weathering

Explanation:

andreyandreev [35.5K]3 years ago
3 0

Answer: C. Chemical Weathering

Explanation:

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Solve 13.004+3.09+112.947
Mashcka [7]

Answer:

The answer is 129.041

Explanation:

Because when you add desimals you need to keep them lined up and not uneven

4 0
3 years ago
A 0.473 kg ice puck, moving east with a speed of 2.76 m/s, has a head-on collision with a 0.819 kg puck initially at rest. Assum
Gekata [30.6K]

Answer:

The final speed of puck 1 is 0.739 m/s towards west  and puck 2 is 2.02 m/s towards east .

Explanation:

Let us consider east as positive direction and west as negative direction .

Given

mass of puck 1 , m_1= 0.473 kg

mass of puck 2 , m_2= 0.819 kg

initial speed of puck 1 , u_1=2.76\frac{m}{s}

initial speed of puck 2 , u_2=0.00\frac{m}{s}

Final speed of puck 1 and puck 2 be v_1\, and\, v_2  respectively

Apply conservation of linear momentum

m_1u_1+m_2u_2=m_1v_1+m_2v_2

=>0.473\times 2.76+0.0=0.473\times v_1+0.819\times v_2

=>1.594=0.5775\times v_1+ v_2 -----(A)

Since collision is perfectly elastic , coefficient restitution e=1

u_2-u_1=v_1-v_2

=>0-2.76=v_1-v_2 ------(B)

From equation (A) and (B)

v_1=-0.739\frac{m}{s}

and v_2=2.02\frac{m}{s}

Thus the final speed of puck 1 is 0.739 m/s towards west  and puck 2 is 2.02 m/s towards east .

       

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3 years ago
What is a precipitate?
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hope this helps :)

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Fast Communication, can be used for good and can be used for bad hackers.
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