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konstantin123 [22]
4 years ago
12

Although we have discussed single-slit diffraction only for a slit, a similar result holds when light bends around a straight, t

hin object, such as a strand of hair. In that case, a is the width of the strand. From actual laboratory measurements on a human hair, it was found that when a beam of light of wavelength 633.0 nm was shone on a single strand of hair, and the diffracted light was viewed on a screen 1.25 m away, the first dark fringes on either side of the central bright spot were 5.06 cm apart. How thick was this strand of hair???
Physics
1 answer:
user100 [1]4 years ago
8 0

Answer:

The width of the strand of hair is   1.96 10⁻⁵ m

Explanation:

For this diffraction problem they tell us that it is equivalent to the diffraction of a single slit, which is explained by the equation

<h3>       a sin θ =±  m λ </h3><h3 />

Where the different temrs are: “a” the width of the hair, λ the wavelength, θ the angle from the center, m the order of diffraction, which is the number of bright rings (constructive diffraction)  

We can see that the diffraction angle is missing, but we can find it by trigonometry, where L is the distance of the strand of hair to the observation screen and "y" is the perpendicular distance to the first minimum of intensity

        L = 1.25 m 100 cm/1m   = 125 cm

       y = 5.06 cm  

      Tan θ = y/L

      Tan θ = 5.06/125

      θ = tan⁻¹ ( 0.0405)

      θ =  2.32º

With this data we can continue analyzing the problem, they indicate that they measure the distance to the first dark strip, thus m = 1

     a = m λ / sin θ

     a = 1 633 10⁻⁹ 1.25/sin 2.3

     a = 1.96 10⁻⁵ m  

     a = 0.0196 mm

The width of the strand of hair is   1.96 10⁻⁵ m

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Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the ce
Elena L [17]

Answer:

The value is  \lambda =  900 \ nm

Explanation:

From the question we are told that

   The width of the slit is  a =  0.15 \ mm = 0.00015 \  m

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      The width of the central maximum is y =  0.75 \ cm  = 0.0075 \ m

Generally the width of the central maximum is mathematically represented as

         y   =  \frac{m *  D  *  \lambda}{a}

Here  m is the order of the fringe and given that we are considering the central maximum, the order will be  m =  1  because the with of the central maximum separate's the and first maxima

So

        \lambda     =     \frac{a y}{ m *  D }

=>     \lambda     =     \frac{ 0.000015 *  0.0075}{ 1  *  1.2 }

=>     \lambda     =   900 *10^{-9} \  m

=>      \lambda =  900 \ nm

6 0
3 years ago
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Masja [62]

Answer:

Option 4

Explanation:

During heating actually heat transfer takes place from a body at higher temperature to a body at lower temperature and the heat transfer takes place until both attain the same temperature  

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So in this case assuming that both the systems have same mass then the energy will leave the system with greater thermal energy and go into the system with less thermal energy as the system with greater thermal energy in this case will be at higher temperature and we are considering this assumption because thermal energy not only depends on temperature but also depends on mass of the system

7 0
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Just from a qualitative analysis we can tell the mass it needs to go upwards. How much we determine with the fact that the increase will be - in absolute value - equal to the work gravity does on it to go down that same distance.

Fixed that work being 1 kJ, we get

\vec F \cdot \vec{ \Delta h} = |F| |\Delta h| cos 0 = ( 9.8 N )\Delta h \cdot 1 = 10^3 J\\\Delta h = \frac {10^3}{9,8} m \approx 102 m

4 0
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