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3 years ago

12

What do we call changes between solid liquid and gaseous forms of a substance

2 answers:

Nadusha1986 [10]3 years ago

6 0

Answer:

a change of state

Explanation:

const2013 [10]3 years ago

5 0

<u>We call changes between solid liquid and gaseous forms of a substance as phase change or change of state.</u>

<u>Explanation:</u>

To change a substance from one state to another, extreme temperatures or pressures are required. Sometimes when a substance doesn't change states we should use all the ideas when that happens. To create a solid, we should decrease the temperature by a huge amount and then add pressure. For example, oxygen will solidify at -361.8 degrees Fahrenheit at standard pressure. However, it will freeze at warmer temperatures when the pressure is increased.

Phase changes happen when a substance reach some special points. Sometimes when a liquid becomes a solid a freezing point or melting point is used to measure the temperature at which a liquid changes into a solid. Some of the phase changes are: Condensation, Freezing, Melting.

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alexdok [17]

Answer:

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Step-by-step explanation:

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What derived unit is used to measure the slope of the line in this graph?

vlabodo [156]

Answer:

C. g/cm³

Explanation:

The slope is measured by calculating the variation of the Y values over the X values between two points on a line.

So, the formula is: Slope = Δy/Δx

That means that we also take the units.

In this case, the Y-axis unit is in g, while the X-axis unit is in cm³.

Dividing a Y-variation over an X-variation will give you g/cm³.

In this case, let's assume the line passes through (10,100) (not exactly, but close enough for the example), and it passes through (0,0)

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3 years ago

Two long, parallel wires are separated by a distance of 2.2 cm. The force per unit length that each wire exerts on the other is

VikaD [51]

Answer:

$i_2 = 7.6 A$

Explanation:

As we know that the force per unit length of two parallel current carrying wires is given as

$F = \frac{\mu_o i_1 i_2}{2\pi d}$

here we know that

$F = 3.6 \times 10^{-5} N/m$

$i_1 = 0.52 A$

d = 2.2 cm

now from above equation we have

$3.6 \times 10^{-5} = \frac{4\pi \times 10^{-7} (0.52)(i_2)}{2\pi (0.022)}$

$3.6 \times 10^{-5} = 4.73 \times 10^{-6} i_2$

$i_2 = 7.6 A$

5 0

3 years ago