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Hunter-Best [27]
3 years ago
7

Determina el grado de pureza de un marmol (CaCO3), si al descomponerse 125 g del mismo se desprenden 20 litros de dióxido de car

bono medidos a 15ºC y 1 atm.
Chemistry
1 answer:
jarptica [38.1K]3 years ago
7 0

Answer:

67.8%

Explanation:

La reacción de descomposición del CaCO₃ es:

CaCO₃ → CO₂ + CaO

<em>Donde 1 mol de CaCO₃ al descomponerse produce 1 mol de CO₂ y 1 mol de CaO.</em>

Usando la ley general de los gases, las moles de dioxido de carbono son:

PV = nRT.

<em>Donde P es presión (1atm), V es volumen (20L), n son moles de gas, R es la constante de los gases (0.082atmL/molK) y T es temperatura absoluta (15 + 273.15 = 288.15K). </em>Reemplazando los valores en la ecuación:

PV / RT = n

1atmₓ20L / 0.082atmL/molKₓ288.15K = 0.846 moles

Como 1 mol de CO₂ es producido desde 1 mol de CaCO₃, las moles iniciales de CaCO₃ son 0.846moles.

La masa molar de CaCO₃ es 100.087g/mol. Así, la masa de 0.846moles de CaCO₃ es:

0.846moles ₓ (100.087g / mol) = <em>84.7g de CaCO₃</em>

Así, la pureza del marmol es:

(84.7g de CaCO₃ / 125g) ₓ 100<em> = </em>

<h3>67.8%</h3>
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Answer:

0.78 atm

Explanation:

Step 1:

Data obtained from the question. This includes:

Mass of CO2 = 5.6g

Volume (V) = 4L

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Pressure (P) =?

Step 2:

Determination of the number of mole of CO2.

This is illustrated below:

Mass of CO2 = 5.6g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Number of mole CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 5.6/44

Number of mole of CO2 = 0.127 mole

Step 3:

Determination of the pressure in the container.

The pressure in the container can be obtained by applying the ideal gas equation as follow:

PV = nRT

The gas constant (R) = 0.082atm.L/Kmol

The number of mole (n) = 0.127 mole

P x 4 = 0.127 x 0.082 x 300

Divide both side by 4

P = (0.127 x 0.082 x 300) /4

P = 0.78 atm

Therefore, the pressure in the container is

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