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gladu [14]
4 years ago
9

5.6 g of solid CO2 is put in an empty sealed 4.00 L container at a temperature of

Chemistry
1 answer:
tresset_1 [31]4 years ago
3 0

Answer:

0.78 atm

Explanation:

Step 1:

Data obtained from the question. This includes:

Mass of CO2 = 5.6g

Volume (V) = 4L

Temperature (T) =300K

Pressure (P) =?

Step 2:

Determination of the number of mole of CO2.

This is illustrated below:

Mass of CO2 = 5.6g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Number of mole CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 5.6/44

Number of mole of CO2 = 0.127 mole

Step 3:

Determination of the pressure in the container.

The pressure in the container can be obtained by applying the ideal gas equation as follow:

PV = nRT

The gas constant (R) = 0.082atm.L/Kmol

The number of mole (n) = 0.127 mole

P x 4 = 0.127 x 0.082 x 300

Divide both side by 4

P = (0.127 x 0.082 x 300) /4

P = 0.78 atm

Therefore, the pressure in the container is

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Answer:

C. matter

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3 years ago
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3 years ago
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A sample of nitrogen containing 3.0×10^23 molecules has the same number of molecules as a sample containing
Daniel [21]

Answer:

D) 0.50 mole of Ne

Explanation:

Given data:

Number of molecules of nitrogen = 3.0×10²³ molecules

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Solution:

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0.25 mol × 6.022×10²³ molecules / 1 mol

1.51×10²³ molecules

B) 2.0 moles of He.

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2.0 mol × 6.022×10²³ molecules / 1 mol

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1 mole = 6.022×10²³ molecules

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0.50 mol × 6.022×10²³ molecules / 1 mol

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3 years ago
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A sample of a gas (1.50 mol) is contained in a 15.0 l cylinder. the temperature is increased from 100 °c to 150 °c. what is the
pav-90 [236]

<u>Given:</u>

Moles of gas, n = 1.50 moles

Volume of cylinder, V = 15.0 L

Initial temperature, T1 = 100 C = (100 + 273)K = 373 K

Final temperature, T2 = 150 C = (150+273)K = 423 K

<u>To determine:</u>

The pressure ratio

<u>Explanation:</u>

Based on ideal gas law:

PV = nRT

P= pressure; V = volume; n = moles; R = gas constant and T = temperature

under constant n and V we have:

P/T = constant

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substituting for T1 and T2 we get:

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Ans: The pressure ratio is 1.13


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3 years ago
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