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Maru [420]
3 years ago
10

What is 1 mol / 66.04g ​

Chemistry
1 answer:
____ [38]3 years ago
5 0

Answer:

15.142338 mol/kg

Explanation:

(1 mole) / (66.04 grams)

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Urgent!! A chemist measured 5.2 g copper(II) bromide tetrahydrate (CuBr2•4(H2O)). How many moles were measured out? Answer in un
bezimeni [28]
  The  moles  which  were   measured  out  is  calculated  using  the  following  formula

moles  =  mass/molar   mass

molar mass  of  CuBr2.4H20  =   63.5  Cu + (  2  x79.9)  br  + ( 18  x4_)  h20  =  295.3  g/mol

moles  is therefore=  5.2 g/  295.3 g/mol=  0.0176 moles
4 0
3 years ago
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I/3 of 12 = 2/3 of<br>please help at 11 o'clock am it needs to be done ​
Nostrana [21]

Answer:

6

Explanation:

This question is seeking for an equivalent of one expression. The first expression says 1/3 of 12, which means 1/3 × 12 = 4. To find 2/3 of a number that will give us 4, we say

Since; 1/3 of 12 is 4

Then, 4 = 2/3 of x, where x is the number, which when multiplied by two-third (2/3) will result to 4.

4 = 2/3 × x

4 = 2x/3

Cross multiply

2x = 3 × 4

2x = 12

x = 12/2

x = 6.

This means that; 1/3 of 12 = 2/3 of 6

4 0
2 years ago
When might a dominant trait appear?
daser333 [38]

Answer:

A dominant allele will always allow a specific trait to show up no matter if we have two dominant copies (BB) or just one (Bb). A trait from a recessive allele will only appear if it is paired with another recessive allele

Explanation:

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7 0
2 years ago
Drag each label to the correct location on the equation. Each label may be used more than once.
elena-14-01-66 [18.8K]
HCl is an acid, C5H5N is a base, Cl is an acid, and HC5H5N is an acid.

Hope this helps! If so, brainliest would be appreciated!
8 0
2 years ago
Consider the reaction of 2.5 grams of Li (s) reacting with 0.5 grams of N2 (g) to produce Li3N (s). A) How many total grams of L
vaieri [72.5K]

Answer:

A) The amount in grams of Li₃N produced is 1.243 g

B) N₂, is the limiting reagent

The mass of the non-limiting reagent, Li, remaining after the reaction is completed is 1.757 g

Explanation:

The given parameters are;

The mass of Li(s) = 2.5 grams

The mass of N₂ (g) = 0.5 grams

The chemical equation for the reaction can be presented as follows;

6 Li (s) + N₂ (g) → 2 Li₃N

Therefore, 6 moles of Li reacts with 1 mole of N₂  to produce 2 moles of Li₃N

The molar mass of Li = 6.941 g/mol

The molar mass of N₂ = 28.0134 g/mol

The number of moles of a reactant or product, n is given by the relation;

n = Mass of substance/(Molar mass of the substance)

For lithium, Li, n = 2.5/6.941 = 0.3602 moles

For Nitrogen gas, N₂, n = 0.5/28.0134  = 0.01785 moles

A) Given that 1 mole of  N₂ to produces 2 moles of Li₃N

0.01785  moles of  N₂ will produces 2×0.01785 = 0.0357 moles of Li₃N

The molar mass of Li₃N = 34.83 g/mol

The mass of Li₃N = 34.83 g/mol × 0.0357 moles = 1.243 g

B) 6  moles of Li reacts with 1 mole of N₂ to produce 2 moles of Li₃N

0.3602 moles will reacts with 1/6×0.3602 = 0.06003 mole of N₂

Therefore, N₂, is the limiting reagent and we have;

0.01785  moles of  N₂ will react with 6×0.01785 = 0.1071  moles of Li

The number of of moles of Li left = 0.3602 - 0.1071 =0.2531 moles

The mass of lithium left = 0.2531 moles × 6.941 g/mol = 1.757 g

The mass of lithium remaining after the reaction is completed = 1.757 g.

4 0
3 years ago
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