Ionization energy is the energy needed to remove one electron from an atom in the gaseous state.
Ionization energy (IE) is the force needed to ionize a neutral atom or cation when it is in its gaseous state. Ionization potential is another name for IE. Ionization energy is conceptually defined as an element's affinity for its outermost electron (an electron it already has in its valence shell).
The least amount of energy needed to ionize an atom is needed to remove an electron from its ground state. Across the periodic table, there is a regular increase in ionization energy from top to bottom and left to right.
To learn more about Ionization energy visit:brainly.com/question/28385102
#SPJ4
Answer:
(a) 133.33nm
(b) 600nm
(c) 7,600nm
Explanation:
The concentration of Y can be determined by using the formula:
where;
[L] = concentration of the binding ligand.
kd = 400 nm
Thus:
When Y = 0.25; we get :
0.25 (400 + [L]) = [L]
100 + 0.25[L] = [L]
100 = [L] - 0.25 [L]
100 = 0.75 [L]
[L] = 100/0.75
[L] = 133.33 nm
At, Y = 0.6
0.6 (400 + [L]) = [L]
240 + 0.6[L] = [L]
240 = [L] - 0.6 [L]
240 = 0.4 [L]
[L] = 240/0.4
[L] = 600 nm
At, Y = 0.95
0.95 (400 + [L]) = [L]
380 + 0.95[L] = [L]
380 = [L] - 0.95 [L]
380 = 0.05 [L]
[L] = 380/0.05
[L] = 7600 nm