On the outermost layer of the rings (where the electrons are)
830 mL
The volume of an 2.3 m solution with 212 grams of calcium chloride (cacl2) dissolved is 830 mL.
The solution has a concentration of 2.3 mol/L.
<h3>a) Moles of CaCl2</h3>
Molar mass of CaCl2 = 110.98 g/mol
Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)
= 1.910 mol CaCl2
<h3>b) Volume of solution</h3>
V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution
= 830 mL solution
<h3>How much CaCl2 is there in the solution by molarity?</h3>
- The number of moles is 0.125 x 2 = 0.25 mol since the molarity is 2.0M.
- To get the answer of 27.745 g, simply multiply this by the molar mass of calcium chloride, which is 110.98 g/mol.
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The molarity of the solution made by dissolving 0.05 mole of HCl in 2 L of H₂O is 0.025 M
<h3>What is molarity? </h3>
Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the molarity </h3>
- Mole of HCl = 0.05 mole
- Volume = 2 L
- Molarity =?
Molarity = mole / Volume
Molarity = 0.05 / 2
Molarity = 0.025 M
Thus, the molarity of the solution is 0.025 M
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