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3 years ago

Identify the type of solid for FeF3

Chemistry

1 answer:

salantis [7]3 years ago

7 0

Answer:

it is iron and flourine gas

Explanation:

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Coach Ramirez made a cup of tea and stirred it with a spoon. The spoon became warm, How was the heat from the tea transferred to

shtirl [24]

Conduction conduction is when things heat up when they are touching

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3 years ago

What is more difficult to melt a polar covalent molecule are non-polar molecule?

Fynjy0 [20]

Answer:

by having positive and negative ends and stronger intermolecular forces of attraction.

Explanation:

hope this helps

plz mark brainiest

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2 years ago

Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C.

Ad libitum [116K]

Explanation:

The given data is as follows.

Concentration = 0.1 $mol/dm^{3}$

= 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

= $6.022 \times 10^{25} ions/m^{3}$

T = $30^{o}C$ = (30 + 273) K = 303 K

Formula for electric double layer thickness ( $\lambda_{D}$ ) is as follows.

$\lambda_{D}$ = $\frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}$

where, $n^{o}$ = concentration = $6.022 \times 10^{25} ions/m^{3}$

Hence, putting the given values into the above equation as follows.

$\lambda_{D}$ = $\sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}$

= $\sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}$

= $9.669 \times 10^{-10}$ m

or, = $9.7 A^{o}$

= 1 nm (approx)

Also, it is known that $\lambda_{D}$ = $\sqrt \frac{1}{n^{o}}$

Hence, we can conclude that addition of 0.1 $mol/dm^{3}$ of KCl in 0.1 $mol/dm^{3}$ of NaBr " $\lambda_{D}$ " will decrease but not significantly.

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3 years ago

How many moles of carbon are in 7.87*10^7 carbon atoms

bonufazy [111]

There is 7 moles in C

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3 years ago

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The kinetic theory assumes that collisions of gas particles are perfectly elastic. What does this statement mean?

In-s [12.5K]

<span>Stating that collisions of gas particles are perfectly elastic means that no kinetic energy is lost when the gases collide, and no kinetic energy is gained. Some of the properties of gases include volume, pressure, thermal conductivity, pressure, and viscosity.</span>

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3 years ago

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