Answer:
When truck is at rest while student is under motion
Explanation:
Since it is obvious that the mass of a truck is more than that of a student, we know that momentum is a product of mass and velocity
P=mv where m represent mass, v is velocity. When the student has more speed than that of truck, he exerts more momentum. The only way a student can exert more momentum is by having more speed while the truck is at rest. In such case, the momentum of truck will be zero while momentum of student will have a value
Answer:
The percentage of the weight supported by the front wheel is A= 19.82 %
Explanation:
B] Let the mass of plane be m, force on backwheels be Nb and nosewheel be Nn
Torque equation about nose wheel,
mg*(2.58-0.8) - Nb *(3.02-0.8) = 0
Nb = mg*(2.58-0.8)/(3.02-0.8) = 0.8018 mg
Nn = mg - Nb = (1-0.8018) mg = 0.1982mg
Weight percentage supported by front wheel = 19.82% answer
Answer:
1472.98 m
Explanation:
Data provided:
Speed of circular looping, v = 340 m/s
Acceleration, a = 8g
here,
g is the acceleration due to the gravity = 9.81 m/s²
Now,
the centripetal acceleration is given as,
r is the radius of the loop
on substituting the respective values, we get
or
r = 1472.98 m
Answer:
Explanation:
Given
Distance = 4.0m
Time = 5.0 mins = 300secs
Required
Average speed
Average speed = Distance/Time
Average speed = 4.0/300
Average speed = 0.01333m/secs
Hence the average speed of the snail is 0.01333m/s
