All categories

4 years ago

Please help !! Science question

Chemistry

1 answer:

Lelu [443]4 years ago

3 0

The answer is 2Eu + 3H2O —> Eu2O3+3H2.
Or in other words, change the first one to 3 and the second to 3 as well.

You might be interested in

What is the representative unit in a molecular compound

Anastasy [175]

Answer:

A.) A molecule

Explanation:

3 0

3 years ago

Read 2 more answers

What is required to move from one state or phase of matter to the next

tigry1 [53]

energy is required to move from one state or phase of matter to the next. Energy is used to make a liquid into a gas or a solid into a liquid.

7 0

4 years ago

A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o

Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

$\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }$

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

$\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}$

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0

4 years ago

Which statement best describes alpha decay?(1 point)

Veseljchak [2.6K]

Answer:

After the ejection of an alpha particle, the remaining nucleus has a mass number that is four less and an atomic number that is two less, so alpha decay is a type of nuclear fission.

6 0

3 years ago

What volume of oxygen at STP is requieres for the complete combustion of 100.50 mL of C2H2

malfutka [58]

The volume of oxygen at STP required would be 252.0 mL.

<h3>Stoichiometic problem</h3>

The equation for the complete combustion of C2H2 is as below:

$2C_2H_2 + 5O_2 --- > 4CO_2 + 2H_2O$

The mole ratio of C2H2 to O2 is 2:5.

1 mole of a gas at STP is 22.4 L.

At STP, 100.50 mL of C2H2 will be:

100.50 x 1/22400 = 0.0045 mole

Equivalent mole of O2 according to the balanced equation = 5/2 x 0.0045 = 0.01125 moles

0.01125 moles of O2 at STP = 0.01125 x 22400 = 252.0 mL

Thus, 252.0 mL of O2 gas will be required at STP.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

7 0

2 years ago