Please solve question 75
2 answers:
<h3>Answer: C) 36</h3>
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Explanation:
Check out the attached image below. Basically I drew out the given diagram and then I added the variables a,b,c,d,e,f,g. Those variables represent the side lengths of the 7 squares. Each square has a perimeter of 4*s where s is the side length, but we dont consider the side that is running along the dashed line (that connects P directly to Q). So we have 3 sides per square added up.
The first square has us travel a distance of 3*a, then the second square a distance of 3*b and so on. Overall, the total distance traveled is
3a+3b+3c+3d+3e+3f+3g = 3(a+b+c+d+e+f+g)
The goal is to figure out what a+b+c+d+e+f+g is equal to. This is equal to the length of segment PQ since the 7 letters are pieces of segment PQ (i.e., I'm using the segment addition postulate).
In other words,
a+b+c+d+e+f+g = 12
3(a+b+c+d+e+f+g) = 3*12
3(a+b+c+d+e+f+g) = 36
Total distance traveled = 36
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Answer:
Distance from the airport = 894.43 km
Step-by-step explanation:
Displacement and Velocity
The velocity of an object assumed as constant in time can be computed as
Where is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as
The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as
The displacement of the plane in 2 hours is
Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are
The displacement in 1 hour is
The total displacement is the vector sum of both
The distance from the airport is the module of the displacement: