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Karolina [17]
3 years ago
14

All of the following are considered anxiety disorders EXCEPT

Chemistry
1 answer:
kenny6666 [7]3 years ago
5 0

obsessive compulsive disorder because OCD is a neurobiological disorder — not a condition that is caused by action or inaction.

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100POINTS!!!!<br><br> Label each reaction to either homogeneous OR heterogeneous
liraira [26]
First is homogeneous and so is the third. second is heterogeneous
8 0
2 years ago
In the lewis structure of ch3oh, how many lone pairs of electrons are there? in the lewis structure of ch3oh, how many lone pair
Lunna [17]
The structure of Methanol (CH₃OH) is shown below. This structure contains 2 lone pair of electrons on oxygen (highlighted red). Electronic configuration of oxygen is,

                        Oxygen  =  8  =  1s², 2s², 2px², 2py¹, 2pz¹

There are six electrons in valence shell of oxygen, among these six electrons two electrons are unpaired and involved in forming covalent bond with hydrogen and carbon, while remaining 4 electrons in pair (i.e. 2s², 2px²) exists as lone pairs.

7 0
3 years ago
How many grams of H2O are in 34.2 grams of NAOH<br> Need ASAP
Brrunno [24]

Answer:

15.438g H2O

Explanation:

First you need to find the reaction equation:

2H2O+2Na=2NaOH + H2

Hydrogen is a diatomic molecule so it will have a subscript of 2 on the right hand side. From there we can balance the reaction.    

Then we can use stoichiometry:

34.2g NaOH * (1 mol NaOH/39.908g NaOH) * (2 mol H2O/2 mol NaOH) * (18.015g H2O/1 mol H20) = 15.438g H2O

It is important that when you use stoichiometry that all your units cancel out until you only have the unit you want.

3 0
2 years ago
Which statement describes a chemical property of oxygen
grin007 [14]
Oxygen can combine with a metal to produce a compound
8 0
3 years ago
Read 2 more answers
How many moles of electrons must be transferred to plate out 110 g of manganese (MW ~ 55g/mol) from a solution of permanganate (
ololo11 [35]

Answer:

14 mol e⁻

Explanation:

Step 1: Write the balanced half-reaction for the reduction of permanganate to manganese

8 H⁺(aq) + 7 e⁻ + MnO₄⁻(aq) ⇒ Mn(s) + 4 H₂O(l)

Step 2: Calculate the moles corresponding to 110 g of manganese

The molar mass of Mn is 55 g/mol.

110 g × 1 mol/55 g = 2 mol

Step 3: Calculate the number of moles of electrons needed to produce 2 moles of Mn

According to the half-reaction, 7 moles of electrons are required to produce 1 mole of Mn.

2 mol Mn × 7 mol e⁻/1 mol Mn = 14 mol e⁻

8 0
3 years ago
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