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SSSSS [86.1K]
3 years ago
13

What is the activity of a 54.7 μCi sample of carbon-14 in becquerels?

Chemistry
1 answer:
Alexus [3.1K]3 years ago
8 0
To calculate the activity of carbon-14 in becquerels, we need a conversion factor to multiply to the value given above. Base on my research, I found that <span>1 Ci = 3.70x10^10 Bq. We convert as follows:

</span>54.7 μCi = 54.7 x 10^-6 Ci ( 3.70x10^10 Bq / 1 Ci ) = 2.02 x 10^6 Bq

Hope this answers the question. Have a nice day.
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If a 250.0 mL sealed plastic bag starts out at a temperature of 19.0 °C and after sitting in the sun reaches a temperature of 60
Marizza181 [45]

Answer:

D

Explanation:

If the pressure remains constant then the temperature and Volume are all that you have to consider.

Givens

T1 = 19oC = 19 + 273 = 292o K

T2 = 60oC = 60 + 273 = 333oK

V1 = 250 mL

V2 = x

Formula

V1/T1 = V2/T2

250/292 = x/333                

Solution.

The solves rather neatly.  Multiplly both sides by 333

250*333 / 292 = 333 *x / 333

Do the multiplication

250 * 333 / 292 = x

83250 / 292 = x

Divide by 292

x = 285.1 mL

The answer is D

8 0
3 years ago
why is it harder to remove an electron from fluorine than from carbon? to put it another way, why are the outermost electrons of
Verizon [17]

It is harder to remove an electron from fluorine than from carbon because the size of the nuclear charge in fluorine is larger than that of carbon.

The energy required to remove an electron from an atom is called ionization energy.

The ionization energy largely depends on the size of the nuclear charge. The larger the size of the nuclear charge, the higher the ionization energy because it will be more difficult to remove an electron from the atom owing to increased electrostatic attraction between the nucleus and orbital electrons.

Since fluorine has a higher size of the nuclear charge than carbon. More energy is required to remove an electron from fluorine than from carbon leading to the observation that;  it is harder to remove an electron from fluorine than from carbon.

Learn more: brainly.com/question/16243729

6 0
3 years ago
#1: The element that loses electrons in a chemical reaction is said to have been which of the following?
Mrrafil [7]
#1: The element that loses electrons in a chemical reaction is said to have been which of the following? A. reduced

B. oxidized

C. combusted

D. rusted

**idk, is it reduced or oxidized??

Answer: oxidized. The element that loses electrons increases its oxidation number (becomes more positve or less negative) and this is oxidation.


Which type of reaction occurs if one element gains electrons and another loses electrons?

A. combustion

B. synthesis

C. oxidation-reduction

D. double-displacement

**my answer: C

Yes, oxidation-reduction

#3: What is the oxidation number for phosphorus in H4P2O7?

A. +5

B. +3

C. +1

D. - 1

**my answer: A. +5

This is the way to calculate it 4(+1) + 2x + 7(-2) = 0 => x = +5



#4: What is the oxidation number for phosphorus in Na2HPO3?

A. +5

B. +3

C. +1

D. - 1

**my answer; B. +3

is that right??

Right

2(+1) + 1 + x + 3(-2) = 0 => x = 6 -1 -2 = 3 (positive)
5 0
3 years ago
Read 2 more answers
Calculate the number of atoms in 3 moles of carbon atoms​
creativ13 [48]

Answer:

1,806,000,000,000,000,000,000,000 atoms.

Explanation:

1 mol of anything is 6.022*10^23 units

1 mol carbon atoms = 6.022*10^23 carbon atoms

3 mol carbon atoms = 3*6.022*10^23 = 1.8*10^24 atoms

Correctly - your answer should have only 1 significant digit: 2 * 10^24 atoms.

6 0
2 years ago
Which of the following is most likely an indication of a chemical change?
gayaneshka [121]

Answer:

B.

Explanation:

Because when a pistol is fired, chemical changes happen to light the gunpowder or whatever substance to create the noise or effect.

5 0
2 years ago
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