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zvonat [6]
4 years ago
7

What would happen to the results if the plastic wrap was dirty in a water filtration experiment?​

Chemistry
1 answer:
weeeeeb [17]4 years ago
4 0

Answer:

The plastic wrap of the covered cup acts like the atmosphere, and traps the water vapor. In a real cloud, the water vapor cools back into liquid water. In the covered cup, the air can only hold so much vapor, and the vapor condenses back to liquid water forming a “rain cloud” on the plastic wrap.

Explanation:

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How much heat is required to raise the temperature of 10.35g of CCl4 from 32.1°c to 56.4°c
Travka [436]
We are going to use this formula:

Q = M*C*ΔT

when Q is the heat required 

M is the mass of CCl4 = 10.35 g

C is the specific heat capacity of CCl4 = 0.874J/g.c

and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C

∴ Q = 10.35g * 0.874 * 24.3 °C

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4 0
3 years ago
A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in K
SCORPION-xisa [38]

The temperature of the gas sample is 813 K.

<u>Explanation:</u>

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

Pressure, P = 429 mm Hg = 0.56 atm

Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

Mass = 0.211 g

Molar mass of carbon di oxide = 44.01 g / mol

Moles, n = $\frac{given mass}{molar mass} = \frac{0.211 g}{44.01 g/mol}

              = 0.0047 mol

Now, we have to plugin the above values in the above equation, we will get the temperature as,

$T= \frac{PV}{nR}

T = $\frac{0.56  \times 0.56}{0.08205 \times 0.0047}

 = 813 K

So the temperature of the gas sample is 813 K.

5 0
4 years ago
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