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Bingel [31]
3 years ago
11

What is the molality of a solution made by dissolving 137.9g of sucrose in 414.1g of water? The density of the solution is 1.104

g/ml.
Chemistry
1 answer:
prisoha [69]3 years ago
5 0

Answer:

Molality of solution = 0.973 m

Explanation:

Molality : It is defined as the moles of the solute per Kg mass of solvent.It is not temperature dependent.

Solute = Substance which is present in less quantity in the solution is called the solute. Here ,<u><em> Sucrose is the solute.</em></u>

Solvent = Substance which is present in more quantity is the solvent.<em><u> Here water is solvent.</u></em>

Molality=\frac{moles\ of\ solute}{mass\ of\ solvent}

Density = It is defined as the mass per unit volume.

Density=\frac{mass}{Volume}

Mass of Solute = 137.9 g

Moles=\frac{mass}{Molar\ mass}

Molar mass of sucrose =

C_{12}H_{22}O_{11}= 12(mass of C)+22(mass of H)+11(mass of O)

= 12(12)+22(1)+11(16)

= 144+22+176

= 342 g/mol

Moles=\frac{mass}{Molar\ mass}

Moles=\frac{137.9}{342}

Moles=0.403

Moles = 0.403 moles

Mass of Solvent = 414.1 g  (water)

Molality=\frac{moles\ of\ solute}{mass\ of\ solvent(g)}(1000)

Molality =\frac{0.403}{414.1}\times 1000

Molality = 0.973 m

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