Answer:
0.64 g of S
Solution:
The balance chemical equation is as follow,
2 Cu + S ----> Cu₂S
According to equation,
127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S
So,
2.54 g Cu will produce = X g of Cu₂S
Solving for X,
X = (2.54 g * 159 g) / 127 g
X = 3.18 g of Cu₂S
Now, it is confirmed that the reaction is 100% ideal. Therefore,
As,
127 g (2 mole) Cu required = 32 g (1 mole) of S
So,
2.54 g Cu will require = X g of S
Solving for X,
X = (2.54 g * 32 g) / 127 g
X = 0.64 g of S
Answer:
molecular so number 3. ...
Answer:
1.023 J / g °C
Explanation:
m = 37.9 grams
ΔT = 25.0*C
H = 969 J
c = ?
The equation relating these equation is;
H = mcΔT
making c subject of formulae;
c = H / mΔT
c = 969 J / (37.9 g * 25.0*C)
Upon solving;
c = 1.023 J / g °C
Explanation:
The given cell reaction is as follows.
Hence, reactions taking place at the cathode and anode are as follows.
At anode ; Oxidation-half reaction : 
...... (1)
At cathode; Reduction-half reaction : 
....... (2)
Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.
Therefore, net cell reaction is as follows.
Net reaction: 
Thus, we can conclude that the overall cell reaction is as follows.
