C₅H₁₂ + 8O₂ = 5CO₂ + 6H₂O
5CO₂ - 10O
6H₂O - 6O
16O - 8O₂
8 moles of molecular oxygen are consumed
Answer:
Answer in explanation
Explanation:
In the first case, we divide each of the masses by the respective atomic masses:
N =0.615/14 = 0.043928571428571
O = 0.703/16 = 0.0439375
It can be seen here that the values are similar, hence the formula is NO
now let us look at the second data set:
N = 1.27/14 = 0.090714285714286
O = 2.9/16 = 0.18125
We now divide by the smallest
N = 090714285714286/090714285714286 = 1
O = 0.18125/090714285714286 = 2
The formula here is thus NO2.
It can be seen that there are different oxides of nitrogen here which clearly indicates the law of multiple proportion.
Answer:
COOHCOOH + 2OH⁻ ⇄ C₂O₄²⁻ + 2H₂O
Explanation:
The reaction of oxalic acid with a strong base like sodium hydroxide is the following:
COOHCOOH + OH⁻ ⇄ COOHCOO⁻ + H₂O (1)
In this first reaction, the oxalic acid loses one proton. In a second reaction with NaOH, the ion COOHCOO⁻ loses its second proton to form ion oxalate as follows:
COOHCOO⁻ + OH⁻ ⇄ C₂O₄²⁻ + H₂O (2)
The general reaction between oxalic acid and NaOH is (eq 1 + eq 2):
COOHCOOH + 2OH⁻ ⇄ C₂O₄²⁻ + 2H₂O
I hope it helps you!
Answer:
100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.
Explanation:
In the given question it is mentioned that
S1=50%
V2=250ml
S2= 20%
We all know that
V1S1=V2S2
∴V1= V2×S2÷S1
∴V1= V2S2×1/S1
∴V1= 250×20÷50
∴V1= 100ml
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